Django {% url %} when urls with parameters like: url(r'^foo/<parameter>/$', include(some.urls))

Question

i don't find any solution, how to get the url in template with the following configuration (using Django1.3):

urls.py

urlpatterns = patterns('',
    url(r'^/foo/(?P<parameter>\d+)/$', include('bar.urls'), name='foo-url'),
    )

Included url-conf:

bar.urls.py

urlpatterns = patterns('',
    (r'^/bar/$', 'bar.views.index'),
    url(r'^/bar/(?P<parameter2>\d+)/$', 'bar.views.detail', name='bar-url'),
    )

bar.views.py

def detail(request, parameter, parameter2):
    obj1 = Foo.objects.get(id=parameter)
    obj2 = Bar.objects.get(id=parameter2)

Now I try to get the url in template with:

{% url bar-url parameter=1 parameter2=2 %}

I expect to get: /bar/1/foo/2/

Is it posible to use in this case the {% url %}?

Calvin Cheng · Accepted Answer · 2012-11-22 23:18:09Z

4

Yes, you can get your url like this:-

{% url 'bar-url' 1 2 %}

But note that your url configuration should actually be like this:-

urls.py

urlpatterns = patterns('',
    url(r'^/foo/(?P<parameter>\d+)/, include('bar.urls')),
)

bar.urls.py

urlpatterns = patterns('',
    (r'^/bar/$, 'bar.views.index'),
    url(r'^/bar/(?P<parameter2>\d+)/$, 'bar.views.detail', name='bar-url'),
)

There is no foo-url unless you specifically map:-

urls.py

urlpatterns = patterns('',
    url(r'^/foo/(?P<parameter>\d+)/$, 'another.views.foo', name='foo'),
    url(r'^/foo/(?P<parameter>\d+)/, include('bar.urls')),
)

Note that $ means the end of the regular expression.

answered Nov 22, 2012 at 23:18

Calvin Cheng

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1 Comment

pharfe Over a year ago

Thanks for the hint. I got it working now. I make some mistakes when setting the parameter in the url-tag. I use version 1.3, therefor {% url bar-url 1 2 %} works.

aemdy · Accepted Answer · 2012-11-23 00:17:45Z

0

Well, I usually set namespace for included urls to simplify the process:

in root urlpatterns

url(r'^articles/', include('articles.urls', namespace='articles')),

in articles/urls.py

url(r'^(\d+)/$', 'read', name='read'),

url(r'^publish/$', 'publish', name='publish'),

And then in your template you can simply type:

{% url articles:read 1 %}

or

{% url articles:publish %}

More about this here.

answered Nov 23, 2012 at 0:17

aemdy

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1 Comment

pharfe Over a year ago

I'm trying to use namespaces, but it seems not to work with a parameter before the included urls.py. See stackoverflow.com/questions/13788062/…

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