try {
if (x.length == Styles.size()) {
}
else{
throws InputMismatchException ;
}
} finally {
OutputFileScanner.close();
}
I get compile error in method contains code above , is there any way to throw InputMismatchException in else block ?
You need to use the new keyword:
throw new InputMismatchException();
throws" answers and everything, sheesh, I thought I was going to have to answer this one. InputMismatchException isn't even a checked exception, it's a subclass of RuntimeException. +1
RuntimeException bit out as the OP probably isn't declaring it anyway (or at least shouldnt be).A "throws" declaration doesn't go in the method body. If you want to simply throw the Exception, declare it as follows:
public void method() throws InputMismatchException{
if(...) {...
OutputFileScanner.close();
}
else{
OutputFileScanner.close();
throw new InputMismatchException("Uh oh");
}
}
There's no need to use a try statement here. When you call method(), you will use the following:
try{
method();
} catch (InputMismatchException ime){
//do what you want
}
Hope that helps!
You want to create an instance of the exception then throw it. throws is used as part of a method declaration, not to actually throw the exception.
if (x.length == Styles.size()) {
}
else{
throw new InputMismatchException();
}
Declare the method it lives in to throw the exception.
Because OutputStream.close() throws IOException you'll need to throw that too:
void myMethod() throws InputMismatchException, IOException {
// your code, except
throw new InputMismatchException();
}
When you throw exception, then there is no need to try-catch-finally it. try catch finally is necessary when you catch an exception. try the following--
if (x.length == Styles.size()) {
}
else{
throw new InputMismatchException() ;
}
