PHP Regex to match the last occurrence of a string

Question

My string is $text1 = 'A373R12345'
I want to find last none digital number occurrence of this string.
So I use this regular expression ^(.*)[^0-9]([^-]*)
Then I got this result:
1.A373
2.12345

But my expected result is:
1.A373R
(It has 'R')
2.12345

Another example is $text1 = 'A373R+12345'
Then I got this result:
1.A373R
2.12345

But my expected result is:
1.A373R+
(It has '+')
2.12345

I want contain the last none digital number!!
Please help !! thanks!!

Rakesh KR · Accepted Answer · 2014-01-08 18:58:09Z

7

$text1 = 'A373R12345';
preg_match('/^(.*[^\d])(\d+)$/', $text1, $match);
echo $match[1]; // A373R
echo $match[2]; // 12345

$text1 = 'A373R+12345';
preg_match('/^(.*[^\d])(\d+)$/', $text1, $match);
echo $match[1]; // A373R+
echo $match[2]; // 12345

Explanation of regex broken down:

^ match from start of string
(.*[^\d]) match any amount of characters where the last character is not a digit 
(\d+)$ match any digit character until end of string

enter image description here

edited Jan 8, 2014 at 18:58

Rakesh KR

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answered Nov 29, 2012 at 2:59

user1592648

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2 Comments

Nick Hung Over a year ago

It works fine for my situtaion!! thanks!! Could you explain the regular expression for me? I only know.*[^\d] mean you wan to find the last none digital number

Epoc Over a year ago

@crypticツ What tool do you have used?

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