PHP Undefined Index Error - Passing Value From Hidden Input

Question

I am receiving this error when trying to pass a value via hidden input in a form. I have used this multiple times before, and I can't seem to figure out why it is not passing this time in particular.

Code from the form on index:

<form method="post" action="viewchars.php">
    <input type="hidden" name="uname" value="testuser" />
</form>

Code on viewchars.php:

<?php
    $user = $_POST["uname"];
?>

The error states that uname is the undefined index.

I am not trying to get the error to just go away, as I actually need the value being passed for the viewchars.php page.

Ah! You see no submit button because there is no submit button... You do see the problem however! Thank you user! — Finni McFinger
– Finni McFinger, Commented Nov 29, 2012 at 23:53
should work, agree. What happens if the input is made visible? Do you also have a submit button? — FrancescoMM
– FrancescoMM, Commented Nov 29, 2012 at 23:54
What happens if you add the submit button and try with that? — FrancescoMM
– FrancescoMM, Commented Nov 29, 2012 at 23:59
how you are submitting that form? If its not present then probably here is problem - anyways you should check if value exists and handle situation when it is not present (like $user = isset($_POST['uname']) ? $_POST['uname'] : null;). — lupatus
– lupatus, Commented Nov 30, 2012 at 0:27

admoghal · Accepted Answer · 2012-11-30 00:17:58Z

1

add submit button in your html

<form method="post" action="viewchars.php">
    <input type="hidden" name="uname"  value="testuser" />
    <input type="submit" value="Submit"/>
</form>

answered Nov 30, 2012 at 0:17

admoghal

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Comments

Paul · Accepted Answer · 2012-11-29 23:44:36Z

1

You have to make sure the form is submitted before using POST values. So it should be something like

$user = isset($_POST['uname']) ? $_POST['uname'] : '';

answered Nov 29, 2012 at 23:44

Paul

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FrancescoMM · Accepted Answer · 2012-11-30 00:13:38Z

0

If you are sending this via JS make sure you are actually using POST. Have you tried to test on $_REQUEST, instead?

Also, try:

use a submit button just to test
make the input visible and type text to test
change var name
try a print_r($_REQUEST); on the php side to see what is received

edited Nov 30, 2012 at 0:13

answered Nov 30, 2012 at 0:02

FrancescoMM

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Mohammad Ali Nekouie · Accepted Answer · 2014-12-04 05:50:44Z

0

just remove "/" form end of input line! like this...

<form method="post" action="viewchars.php"> <input type="hidden" name="uname" value="testuser" > </form>

answered Dec 4, 2014 at 5:50

Mohammad Ali Nekouie

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Comments

zuperakos · Accepted Answer · 2012-11-29 23:47:34Z

-1

try the following:

$user = $_POST['uname'];

answered Nov 29, 2012 at 23:47

zuperakos

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1 Comment

Finni McFinger Over a year ago

Single or double quotes makes no difference.

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