Using local variable as src on iframe

Question

I need to use the output in the variable $data and put it inside an iframe (or other perhaps) so as to scroll it properly. Please, find the mistake in the following code:

    <?php

    $url = 'http://lema.rae.es/drae/srv/search?id=IwxflJmT9DXX2DMkYs8Z';

    $css = <<<EOT

    <style type="text/css">
     body
       {
       background: #eeeeee;
       }
     .a
       {
        color: green;
       }
    .f
       {
        font-size: 200%;
       }
    .o
       {
        font-size: 80%;
        }
    img
        {
        visibility:hidden;
         }

    </style>
    EOT;

    $data = file_get_contents($url);
    $data = str_replace('</head>', $css.'</head>', $data);
    echo "<iframe id='first' src='$data'
          frameborder='0' 
          width='400px' 
          height='300px' 
          scrolling='yes'
          border-style: none;></iframe>";
    ?>

The problem is probably on the last lines. Instead of the word's definition to appear inside the iframe, an error shows up, saying the object hasn't been found Thanks! enter image description here

instead of the word's definition to appear inside the iframe, an error shows up, saying the object hasn't been found — j1nma
– j1nma, Commented Dec 7, 2012 at 4:35
Please put the explanation of what doesn't work in the body of the question, as well as the exact error message you get, rather than a paraphrase of it. — Andy Lester
– Andy Lester, Commented Dec 7, 2012 at 4:36
@JuanmaAlonso - try changing the iframe attributes as i have posted in answer and let me know if your problem is solved ! — Pankit Kapadia
– Pankit Kapadia, Commented Dec 7, 2012 at 5:01

Pankit Kapadia · Accepted Answer · 2012-12-07 06:30:41Z

3

Change <iframe> to the iframe code given below.:

<?php

$url = 'http://lema.rae.es/drae/srv/search?id=IwxflJmT9DXX2DMkYs8Z';

$css = <<<EOT

<style type="text/css">
 body
   {
   background: #eeeeee;
   }
 .a
   {
    color: green;
   }
.f
   {
    font-size: 200%;
   }
.o
   {
    font-size: 80%;
    }
img
    {
    visibility:hidden;
     }

</style>
EOT;

$data = file_get_contents($url);
$data = str_replace('</head>', $css.'</head>', $data);
/*u have to change src like this. and you need to add style attribute to use border-style: none;
   /* echo "<iframe id='first' src='".$data."'
      frameborder='0' 
      width='400px' 
      height='300px' 
      scrolling='yes'
      style='border-style:none;'></iframe>"; */
//Remove this iframe and simply echo $data
echo '<div style="overflow:scroll;">'.$data.'</div>'; //YOU CAN USE AUTO instead of SCROLL
?>

The output what i am getting is as below:(i have set height:200px; width:500px;)

enter image description here

edited Dec 7, 2012 at 6:30

answered Dec 7, 2012 at 4:57

Pankit Kapadia

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6 Comments

j1nma Over a year ago

i copied the code just as you wrote but still it shows up "object not found"

Pankit Kapadia Over a year ago

@JuanmaAlonso - its showing me Forbidden error showing that

You don't have permission to access /<html><head><link rel="stylesheet" type="text/css" href="/drae/css/I.drae.css+estilosCabDrae.css,Mcc.W_CzH9ApGk.css.pagespeed.cf.w1GLVsE-IR.css"><TITLE>Real Academia EspaÃ±ola. Diccionario Usual.</TITLE><style type="text/css"> body { background: on this server.

j1nma Over a year ago

yes, there is no permission, but there must be a way to put $data into an object or something more editable. If i just leave echo $data , it works, i can change the font and everything, but i would like to put everything together, simply on one object, doesn't have to be an iframe. And, if i link the iframe to $url, it works, but my css changes don't take place....

Pankit Kapadia Over a year ago

@JuanmaAlonso - let me know is it what exactly wanted??

Pankit Kapadia Over a year ago

@JuanmaAlonso - check the updated code with <div>. Specify width and height as you want

|

simon · Accepted Answer · 2012-12-07 04:31:55Z

2

the src attribute on an <iframe/> element takes a URL, not HTML source....

i'm not entirely sure what you want to do, but perhaps you just need to echo your $data ?

answered Dec 7, 2012 at 4:31

simon

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10 Comments

j1nma Over a year ago

so should be then (...) src='$url' ??

simon Over a year ago

well, that will work, but it will load the original page, without your CSS additions

j1nma Over a year ago

so how is the complete way, including my CSS additions ??

simon Over a year ago

did you try just echo $data;? you might have a bit to work through, still, but that seems to be what you're after?

Pankit Kapadia Over a year ago

@JuanmaAlonso - code is changed. Checkout my answer with the output i am getting.

|

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