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How can I do the following in Unix:

1) Variable xxx_yyy=12345
2) Variable aaa=yyy

How can I evaluate xxx_$aaa to give me 12345.

Please advise.

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2 Answers 2

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In bash use indirect parameter expansion:

varname=xxx_$aaa
echo ${!varname}

However, dynamic variable names are usually tricky to handle. Easier to use an associative array:

declare -A xxx
xxx[yyy]=12345
aaa=yyy
echo ${xxx[$aaa]}
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1

In bash (and probably others: specify if you want another), use eval. Don't forget to escape the first $ as shown:

eval echo \$xxx_$aaa
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