Variable inside an object context

Question

How do I make nav_items work in the following context?

params = {
    nav: $('.nav'),
    nav_items: params.nav.find('li')
}

ReferenceError: params is not defined (logically true)

Also tried this:

params = {
    nav: $('.nav'),
    nav_items: nav.find('li')
}

ReferenceError: nav is not defined (what is the right way?)

I know, it can be done using this code:

params = {
    nav: $('.nav'),
    nav_items: null
}
params.nav_items = nav.find('li');

But its interesting, can it be done without an extra code?

Claudio Redi · Accepted Answer · 2012-12-14 12:54:09Z

4

var $nav = $('.nav');
params = {
    nav: $nav,
    nav_items: $nav.find('li')
}

answered Dec 14, 2012 at 12:54

Claudio Redi

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9 Comments

Dziad Borowy Over a year ago

you could wrap values in functions

Claudio Redi Over a year ago

@Steve: I don't see that adding an extra line is something to be worried about. I will use this as it is :)

Mark Over a year ago

$nav becomes a global, I'm trying to make it quite local.

asawyer Over a year ago

@Steve var makes it local.

Mark Over a year ago

I would like to use it for more than 1 element, more than 10 extra elements can make code a bit messy.

|

closure · Accepted Answer · 2012-12-14 13:57:31Z

2

May be too late but could not refrain:

params = (function(a) { 
  return {nav: a, nav_items: a.find('li')};
})($('.nav'));

edited Dec 14, 2012 at 13:57

answered Dec 14, 2012 at 13:46

closure

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3 Comments

closure Over a year ago

@Steve: Saw it after you accepted the answer. Could not avoid answering as your excepted answer does not meet your own required criteria.

asawyer Over a year ago

Inlining the functions would be a bad call according to I would like to use it for more than 1 element, more than 10 extra elements can make code a bit messy.

closure Over a year ago

@asawyer: Can't agree with you more! But Steve's requirement was such.

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