Print all functions output of class in php?

Question

Hi friends i am new to php , and i am trying to learn classes i am trying the following code with which i get all functions *name* described in the class can anybody tell me how can i print the output of functions in the class

<?php
    class dog {
                    public function bark() {
                    print "Woof!\n";
                    }

                    public function legs() {
                    print "four!\n";
                    }
             }

    class poodle extends dog {
      public function yip() {
            print "Yipppppppp!\n";
        }
    }

    $poppy = new poodle;

    //$poppy->bark();
    $class_methods = get_class_methods(new poodle());
    //echo    $class_methods;
        foreach($class_methods as $class_methods1)
        {
        echo $class_methods1.'<br/>';
        }

?>

dognose · Accepted Answer · 2013-01-18 10:40:31Z

1

This should work:

$poodle = new poodle();
$class_methods = get_class_methods($poodle);
//echo    $class_methods;
foreach($class_methods as $class_method)
{
    echo $class_method.'\'s Output: '.$poodle->$class_method()."<br />"; 
}

In general:

If you have a value like $test = "abc" you can evaluate it (in php) to either a variablename, or a function etc.:

$test = "abc";
$test() // equal to abc() - if function abc exists.

echo $$test // equal to echo $abc - if $abc is defined.

$anotherTest = new $test(); // equal to new abc() - if class exists.

edited Jan 18, 2013 at 10:40

answered Jan 18, 2013 at 10:21

dognose

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2 Comments

Rohit Goel Over a year ago

THANKS THATS A PREETY NICE ANSWER WITH THIS I UNDERSTAND BOTH FUNCTION AND ITS OUTPUT

dognose Over a year ago

@RohitGoel Added a general example.

scragar · Accepted Answer · 2013-01-18 10:19:50Z

0

$poppy = new poodle;

$class_methods = get_class_methods($poppy);

foreach($class_methods as $class_method_name)
{
    echo $class_methods_name.' => '
        // Either:
        .$poppy->$class_method_name()
        // OR (prefered method, but more typing)
        .call_user_func(array($poppy, $class_method_name))

        .'<br/>';

}

answered Jan 18, 2013 at 10:19

scragar

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1 Comment

Rohit Goel Over a year ago

thanks for replying but as a beginner this is little hard for me

MrCode · Accepted Answer · 2013-01-18 10:21:11Z

0

A variable can be used in place of the method name to do what you want. Note: you don't need to echo the result of the method calls because your methods all print something but they don't actually return anything.

Demo

$poppy = new poodle;

$class_methods = get_class_methods($poppy);

foreach($class_methods as $class_methods1)
{
   $poppy->$class_methods1() . '<br/>';
}

Outputs

Yipppppppp!
Woof!
four!

answered Jan 18, 2013 at 10:21

MrCode

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