Generate a list of hexadecimal numbers in python

Question

I'm working on a cryptography project and I need to generate all hexadecimal possible numbers (length of the number= 16 bits in binary) and put them in a list in order to use them later.

Any suggestions?

Thanks in advance

Ketouem · Accepted Answer · 2013-01-28 10:38:15Z

1

(Yet) another Python one liner :

a = [hex(x) for x in xrange(0,pow(2, 16))]

EDIT : Given all the comments, we now have :

a = map(hex, xrange(pow(2,16) - 1))

edited Jan 28, 2013 at 10:38

answered Jan 28, 2013 at 10:14

Ketouem

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4 Comments

AI Generated Response Over a year ago

Shouldn't it not have the -1 at the end since xrange generates up to upperlimit-1?

AI Generated Response Over a year ago

You might want to add in map for completeness. a = map(hex,xrange(pow(2,16)))

AI Generated Response Over a year ago

the 0 in xrange should also be superfluous (xrange should start at 0)

NationWidePants Over a year ago

you can also use the struct or binascii libraries to translate.

score 1 · Accepted Answer · 2013-01-27 21:38:43Z

1

Why not generate all the integers from 0 to 2^16-1, and convert to hex? Yes, I know that it could be done more efficiently, but you are doing this ONCE. Why make things difficult?

edited Jan 27, 2013 at 21:38

answered Jan 27, 2013 at 21:27

user85109

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