how to check if a specific file extension exists in a folder using powershell?

Question

I have a root directory that consists of many folders and sub folders. I need to check whether a particular file like *.sln or *.designer.vb exists in the folders or subfolders and output the result in a text file.

For Eg:

$root = "C:\Root\"
$FileType = ".sln",".designer.vb"

the text file will have result somewhat like below:

.sln ---> 2 files
.sln files path ----> 
c:\Root\Application1\subfolder1\Test.sln
c:\Root\Application2\subfolder1\Test2.sln

Any help will be highly appreciated!

Regards, Ashish

TTT · Accepted Answer · 2020-09-22 16:21:55Z

6

Here's a one-liner to determine if at least one file with extension .txt or .ps1 exists in the directory $OutputPath:

(Get-ChildItem -Path $OutputPath -force | Where-Object Extension -in ('.txt','.ps1') | Measure-Object).Count

Explanation: the command tells you the number of files in the specified directory matching any of the listed extensions. You can append -ne 0 to the end, which returns true or false to be used in an if block.

edited Sep 22, 2020 at 16:21

answered Sep 22, 2020 at 16:14

TTT

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1 Comment

Ste Over a year ago

Best answer for me on here +1. In case anyone may want the regex version, here's that. (Get-ChildItem -Path $OutputPath -force | Where-Object Extension -match ('\.jpe?g') | Measure-Object).Count Which will match either jpeg or jpg.

Frode F. · Accepted Answer · 2013-01-31 09:51:24Z

5

Try this:

function Get-ExtensionCount {
    param(
        $Root = "C:\Root\",
        $FileType = @(".sln", ".designer.vb"),
        $Outfile = "C:\Root\rootext.txt"
    )

    $output = @()

    Foreach ($type in $FileType) {
        $files = Get-ChildItem $Root -Filter *$type -Recurse | ? { !$_.PSIsContainer }
        $output += "$type ---> $($files.Count) files"
        foreach ($file in $files) {
            $output += $file.FullName
        }
    }

    $output | Set-Content $Outfile
}

I turned it into a function with your values as default parameter-values. Call it by using

Get-ExtensionCount    #for default values

Or

Get-ExtensionCount -Root "d:\test" -FileType ".txt", ".bmp" -Outfile "D:\output.txt"

Output saved to the file ex:

.txt ---> 3 files
D:\Test\as.txt
D:\Test\ddddd.txt
D:\Test\sss.txt
.bmp ---> 2 files
D:\Test\dsadsa.bmp
D:\Test\New Bitmap Image.bmp

To get the all the filecounts at the start, try:

function Get-ExtensionCount {
    param(
        $Root = "C:\Root\",
        $FileType = @(".sln", ".designer.vb"),
        $Outfile = "C:\Root\rootext.txt"
    )
    #Filecount per type
    $header = @()
    #All the filepaths    
    $filelist = @()

    Foreach ($type in $FileType) {
        $files = Get-ChildItem $Root -Filter *$type -Recurse | ? { !$_.PSIsContainer }
        $header += "$type ---> $($files.Count) files"
        foreach ($file in $files) {
            $filelist += $file.FullName
        }
    }
    #Collect to single output
    $output = @($header, $filelist)    
    $output | Set-Content $Outfile
}

edited Jan 31, 2013 at 9:51

answered Jan 30, 2013 at 7:40

Frode F.

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6 Comments

ashish g Over a year ago

Hi Graimer, Thanks for your response. After I call this function through the command prompt I get: cmdlet set-content at command pipeline pos 1. supply values for the parameters.. and the parameters are endless :(

Frode F. Over a year ago

This happends when you call exactly Get-ExtensionCount ? Did you copy the function 100%? Especially the last line. $output | Set-Content $Outfile. I think you forgot to include $Outfile at the end. Script works on PS2.0 and PS3.0. You could also try to switch the line with $output | Set-Content -Path $Outfile but it shouldn't matter.

ashish g Over a year ago

Yes.. I had missed that :-) But in the output I get .sln--->44 files , .suo ---> files.. but none show the files and file paths.

Frode F. Over a year ago

oh, sorry. forgot about one PS3.0 feature. see updated answer

ashish g Over a year ago

is there a way I can print the output in the manner where all the types of files and their counts come in first and all the file paths come in the last.. .sln--->34 files .suo--->120 files then comes the filepaths

|

Lance U. Matthews · Accepted Answer · 2013-01-30 08:12:59Z

0

This will search the directory $root and its subdirectories for files of type $FileType, including hidden files and excluding directories:

$root = "C:\Root\";
$FileType = "*.sln", "*.designer.vb";
$results = Get-ChildItem -Path $root -Force -Recurse `
    | Where-Object {
        if ($_ -isnot [System.IO.DirectoryInfo])
        {
            foreach ($pattern in $FileType)
            {
                if ($_.Name -like $pattern)
                {
                    return $true;
                }
            }
        }

        return $false;
    }

Note that I've modified the strings in $FileType to be formatted as a wildcard pattern. Then group the files by extension:

$resultGroups = $results | Group-Object -Property 'Extension';

Then loop through each group and print the file count and paths:

foreach ($group in $resultGroups)
{
    # $group.Count: The number of files with that extension
    # $group.Group: A collection of FileInfo objects
    #  $group.Name: The file extension with leading period
    Write-Host "$($group.Name) ---> $($group.Count) files";
    Write-Host "$($group.Name) files path ---->";

    foreach ($file in $group.Group)
    {
        Write-Host $file.FullName;
    }
}

To write the results to a file instead of the console, use the Out-File cmdlet instead of the Write-Host cmdlet.

edited Jan 30, 2013 at 8:12

answered Jan 30, 2013 at 7:42

Lance U. Matthews

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4 Comments

Frode F. Over a year ago

Filter doesn't support array input(multiple fileext.)

Lance U. Matthews Over a year ago

Yes, just realizing that now.

Frode F. Over a year ago

You could however modify it to use if ($FileType -contains $group.Name) { ... in you foreach loop instead of the Filter

Lance U. Matthews Over a year ago

That would work, but then Group-Object would end up processing files and creating groups that might ultimately end up being ignored. Instead, I changed the call to Get-ChildItem to retrieve all files and the filtering is now performed inside of Where-Object. I made a slight change to the format of $FileType to facilitate this.

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