Exit loop from function

Question

I want to break the following loop from a function that was called kind of like shown below.

Function test {
    $i++
    IF ($i -eq 10) {continue}
}

$Computers = "13","12","11","10","9","8","7","6","5","4","3","2","1"
ForEach ($Computer in $Computers) {
    Test
    write-host "Fail"
}

what are you trying to do ? if you want to break, use the break keyword, not continue :) — Loïc MICHEL
– Loïc MICHEL, Commented Feb 3, 2013 at 7:53

Shay Levy · Accepted Answer · 2013-02-03 07:57:04Z

3

If I'm following you...

Function test {
    $args[0] -eq 10
}

$Computers = "13","12","11","10","9","8","7","6","5","4","3","2","1"
ForEach ($Computer in $Computers) {
    if(Test $Computer) {break} else {$Computer}
}

answered Feb 3, 2013 at 7:57

Shay Levy

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1 Comment

Nick W. Over a year ago

yep thats what I am going for just wondering if I could call the break from inside the function so I can keep the main body of the script clean as possible.

BellsAndWhistles · Accepted Answer · 2023-11-21 04:53:42Z

0

I tried, indeed you can.

Function Test ($i) {
    if ($i -eq 10) {continue}
    if ($i -eq 3)  {break}
}

$numbers = "13","12","11","10","9","8","7","6","5","4","3","2","1"
ForEach ($number in $numbers) {
    Test $number
    write-host "$number"
}

Output:

So, 10 is skipped, and it exited the loop on 3.

It's just coding like that is a bad practice, because it's generally not expected from a function to break loops.

Unless the function has a name related to loops. Like "Exit-LoopOnFailure()"

answered Nov 21, 2023 at 4:53

BellsAndWhistles

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