AttributeError: 'str' object has no attribute 'insert'

Question

I'm quite a new programmer and I would be appreciated if you could help me. I have looked on the google but there are a few examples with "Twisted+Tkinter". When i click "Send" button on the window i get this error:

The error is e.insert(0,m) AttributeError: 'str' object has no attribute 'insert'

And the code:

from Tkinter import *
from twisted.internet import reactor, tksupport

class App(object):
    def onQuit(self):
        print "Quit!"
        reactor.stop()

    def onButton(self):
        m=self.entryvar.get()
        e=self.labeltext.get()
        e.insert(0,m)

def __init__(self, master):
    frame = Frame(master)
    frame.pack()

    self.entryvar=StringVar()
    self.mes=Entry(frame,textvariable=self.entryvar)
    self.mes.pack()

    self.labeltext=StringVar()
    self.label=Label(frame,textvariable=self.labeltext)
    self.label.pack()

    q = Button(frame, text="Quit!", command=self.onQuit)
    b = Button(frame, text="Send", command=self.onButton)
    q.pack(side=LEFT)
    b.pack(side=LEFT)

if __name__ == '__main__':
    root = Tk()
    tksupport.install(root)
    app = App(root)
    reactor.run()

What do you expect to happen when you call insert()? You are manipulating a label string as if it is a mutable list, but a str is not a mutable sequence type. — Martijn Pieters
– Martijn Pieters, Commented Feb 28, 2013 at 12:41
I'am trying to change the text on the label "labeltext" with the entry "entryvar" — billwild
– billwild, Commented Feb 28, 2013 at 12:43
For what it's worth this seems to have nothing to do with Twisted. — Glyph
– Glyph, Commented Mar 1, 2013 at 8:37
I am just testing it, if i could solve this problem i'll apply it on twisted — billwild
– billwild, Commented Mar 1, 2013 at 8:41

Martijn Pieters · Accepted Answer · 2013-02-28 12:43:42Z

3

If you want to update the labeltext StringVar, you need to construct a new string value for it. str is an immutable sequence type, and unlike list cannot be modified in-place.

In this case, perhaps you meant to use string concatenation? The following code will set labeltext to m + e, where e is the previous contents of labeltext, effectively prepending m:

def onButton(self):
    m=self.entryvar.get()
    e=self.labeltext.get()
    self.labeltext.set(m + e)

answered Feb 28, 2013 at 12:43

Martijn Pieters

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6 Comments

billwild Over a year ago

Thank you, the error is disappeared but nothing's happened on the window. Any idea?

Martijn Pieters Over a year ago

@billwild: Does entryvar have a value? If it is empty, then labeltext will appear unchanged. You could try debugging this by changing the .set() call to self.labeltext.set('m: ' + m + ', e: ' + e), for example.

billwild Over a year ago

Should i make self.entryvar=StringVar() /n self.entryvar.set("something")

Martijn Pieters Over a year ago

@billwild: No, why would you need to do that? You are merely reading entryvar.

billwild Over a year ago

I don't know what i'm doing, please just instruct me.

|

Vlad Emelianov · Accepted Answer · 2013-02-28 12:48:59Z

1

If you want to replace Label text with Entry text

 def onButton(self):
    entry_text = self.entryvar.get()
    self.labeltext.set(entry_text)

Or if you want to add entry text before label text

 def onButton(self):
    entry_text = self.entryvar.get()
    label_text = self.labeltext.get()
    self.labeltext.set(entry_text + " " + label_text)

answered Feb 28, 2013 at 12:48

Vlad Emelianov

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1 Comment

billwild Over a year ago

The error is disappeared but nothing's happened on the window

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