Error in counting character(s) entered by user using Java

Question

I am supposed to create a program that counts the number of specific types of characters entered by the user. The number of upper case letters, lower case letters, digits (0 through 9) and other characters other than the # sign are counted. The user enters # to exit.

import java.util.Scanner;
public class countchars
{
    public static void main (String args[])
    {
    Scanner input = new Scanner (System.in);

    char sym;
    int up = 0;
    int low = 0;
    int digit = 0;
    int other = 0;

    System.out.print("Enter a character # to quit: ");
    sym = input.next().charAt(0);

    while(sym != '#')
    {
    System.out.print("Enter a character # to quit: ");
    sym = input.next().charAt(0);

    if (sym >= 'a' && sym <= 'z')
        {
        low++;
        }   
    } 

    System.out.printf("Number of lowercase letters: %d\n", low);
    }
}

That's what I have so far for the lowercase count. The problem is when I run the program and enter 4 lowercase letters, it only counts 3.

you could try adding print statements inside your if statement together with your low++ to confirm how many times it entered the statement :) — Oneb
– Oneb, Commented Mar 7, 2013 at 6:29
@EvanKnowles Home Work tag is OBSOLETE -> stackoverflow.com/tags/homework/info — Apurv
– Apurv, Commented Mar 7, 2013 at 6:37

Evan Knowles · Accepted Answer · 2013-03-07 06:32:09Z

4

You have called

input.next()

twice by the first time you count, so the first character is discarded, messing up your count by one.

answered Mar 7, 2013 at 6:32

Evan Knowles

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Comments

Arsen Alexanyan · Accepted Answer · 2013-03-07 06:32:40Z

2

Change like this

while(sym != '#')
    {

    if (sym >= 'a' && sym <= 'z')
        {
        low++;
        }

    System.out.print("Enter a character # to quit: ");
    sym = input.next().charAt(0);

    }

answered Mar 7, 2013 at 6:32

Arsen Alexanyan

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Comments

NPKR · Accepted Answer · 2013-03-07 06:34:05Z

0

don't use two times input.next();

use this

sym = input.next().charAt(0);

    while(sym != '#')
    {
    System.out.print("Enter a character # to quit: ");
    //sym = input.next().charAt(0); removed this line and try

    if (sym >= 'a' && sym <= 'z')
        {
        low++;
        }


    }

answered Mar 7, 2013 at 6:34

NPKR

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