PHP : Sum different values of multidimensional array

Question

I need to sum totals for 'in' and 'ou', [a] through [t] The array.

Array
(
[1] => Array
    (
        [in] => Array
            (
                [a] => 3
                [b] => 0
                [c] => 0
                [d] => 0
                [e] => 0
                [f] => 0
                [o] => 0
                [t] => 3
            )

        [ou] => Array
            (
                [a] => 0
                [b] => 0
                [c] => 1
                [d] => 0
                [e] => 0
                [f] => 0
                [o] => 0
                [t] => 1
            )
    )
[2] => Array
    (
        [in] => Array
            (
                [a] => 0
                [b] => 0
                [c] => 0
                [d] => 0
                [e] => 0
                [f] => 0
                [o] => 0
                [t] => 0
            )

        [ou] => Array
            (
                [a] => 0
                [b] => 0
                [c] => 0
                [d] => 1
                [e] => 2
                [f] => 0
                [o] => 0
                [t] => 3
            )
    )
)

The following is how I am calculating totals 'in'+'ou'. However, I seem to be stuck in a rut when it comes to the individual totals of 'in' a,b,c,d,e,f,t and 'ou' a,b,c,d,e,f,t.

//get day total
foreach($arr as $array){
    foreach($array as $inou){
        foreach(array_keys($inou) as $value){
            if(isset($total[$value])){
                $total[$value] += $inou[$value];
            }else{
                $total[$value] = $inou[$value];
            }
        }
    }
}

The output should look something like

in(
[a] => 3
[b] => 0
[c] => 0
...
[t] => 3
)
ou(
[a] => 0
[b] => 0
[c] => 1
[d] => 1
[e] => 2
[f] => 0
[t] => 4
)

GGio · Accepted Answer · 2013-03-08 23:02:16Z

2

This should get you started:

        $sumIN = 0; 
        $sumOU = 0;
        foreach($arr as $innerArr)
        {
            $sumIN += array_sum($innerArr['in']);
            $sumOU += array_sum($innerArr['ou']);
        }

answered Mar 8, 2013 at 23:02

GGio

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1 Comment

mbunch Over a year ago

I need each total IN(a => total, b => total,...) and ou(a => total, b => total,...)

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