Converting Java Date to Php [duplicate]

Question

How can I format a "Java-Date" in seconds since 1970 to an dd.mm.yyyy HH:MM:SS in php. I have this date as an variable in php:

$date = "1362065364128";

Bora · Accepted Answer · 2015-02-23 09:55:20Z

2

$date = "1362065364128";
$phpDate = date('d.m.y H:i:s', $date/1000);

Bora

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answered Mar 11, 2013 at 8:11

Neophile

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Comments

troelskn · Accepted Answer · 2013-03-11 07:53:59Z

2

It's called a unix timestamp, and you can pass it as the second argument to the date function in php-

answered Mar 11, 2013 at 7:53

troelskn

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hank · Accepted Answer · 2013-03-11 07:59:40Z

1

You can use the PHP method date, note that the three last numbers are milliseconds here, so you need to disregard them first.

$date = "1362065364128";
$formatted = date('Y-m-d H:i:s', intval($date) / 1000);

answered Mar 11, 2013 at 7:54

hank

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user657496 · Accepted Answer · 2013-03-11 07:53:27Z

0

Use the PHP date function, documentation here

answered Mar 11, 2013 at 7:53

user657496