I want to read from standard input, delete all '/', and write the output to standard output. So, a file that contain:
/ab1/1a6/ 17
/a/b/1
will have output:
ab11a6 17
ab1
I think it should be something like this:
read input
sed -r 's/\/[^\/]*\/[^\/]*\/.*/"I not sure what do I need to put in here"/g'
echo $input
I don't really know what do I need to put the the "replace" section. any suggestion?
sed 's./..g'
This will delete all / characters on each line, so you don't need a replace section. You can either use the / as the delimiter and escape it in the text: s/\///g or choose a different punctuation symbol as a delimiter: s./..g
So if you want to transform a file called input.txt and write the output to output.txt:
sed 's./..g' input.txt > output.txt
# or
sed 's./..g' < input.txt > output.txt
The simplest program to do what you've asked is:
tr -d '/'
If you enter that you will get what you wanted for output - no / characters You do not need a read or echo statement
sed will behave the same as others have shown, tr & sed read from stdin and write to stdout by default:
sed 's/\///g'
sedNothing... as shown below:
% echo "/ab1/1a6/ 17" | sed 's/\///g'
ab11a6 17
