Bash, use export and run export in single script

Question

#!/bin/bash
export foo='script...'

bash --program=foo

how do you run the exported "foo"
i've been working with gtkdialog and it is written

#!/bin/bash
export MAIN_DIALOG='...xml code...'

gtkdialog --program=MAIN_DIALOG

the same should be possible with a simple bash script?
i would like this to reduce the number of files i must include
currently each set of bash scripts i write for one program are saved in separate files then executed by the main script.

If the program is in the current working directory then it's judt ./$foo — suspectus
– suspectus, Commented Mar 29, 2013 at 19:24

William Pursell · Accepted Answer · 2013-03-29 19:23:09Z

1

I believe you are just looking for:

bash -c "$foo"

answered Mar 29, 2013 at 19:23

William Pursell

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Barmar · Accepted Answer · 2013-03-29 19:27:33Z

0

To reduce the number of files, you can change the commands from separate scripts to functions in the main script:

cmd() {
  # actions for foo command
}

Then, instead of using bash -c to run them, you can use eval:

foo='cmd ...'

eval "$foo"

answered Mar 29, 2013 at 19:27

Barmar

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