parsing URL in String from JSON

Question

1) I've got a JSON file:

{
  "serverURI":"http://localhost:8080/PocketUNI_API/serverURLs",
  "newsURI":"http://localhost:8080/gateway/rss/rss.xml",
  "modulesURI":"http://localhost:8080/PocketUNI_API/modules"
}

2) I need to get URLs on Java client in String format.

String json = jsonReceiver.makeHttpRequest(URL_SERVER, "GET", params);
JSONArray uris = new JSONArray(json);

Receiver works fine and json shows the correct string received, but when it goes to parsing with JSONArray it throws an error

org.json.JSONException: Value {"serverURI":"http:\/\/192.168.0.... of type org.json.JSONObject cannot be converted to JSONArray.

Question: How to parse json with URL values?

to loop through the multiple json objects using jsonArray object — exomen
– exomen, Commented Apr 9, 2013 at 14:20
the code you posted above dosnt seems to have an array of jsonobject instead it has a single json object and casting obejct to array will give u jsonexception try to extract a single object — Vivek Bajpai
– Vivek Bajpai, Commented Apr 9, 2013 at 14:23
not JSONArray but JSONObject. JSONObject json = new JSONObject(str) — lichengwu
– lichengwu, Commented Apr 9, 2013 at 14:30

user1907906 · Accepted Answer · 2013-04-09 14:15:59Z

1

You don't get a JSONArray but a JSONObject.

JSONObject uris = new JSONObject(json);

answered Apr 9, 2013 at 14:15

user1907906

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Comments

Arun P Johny · Accepted Answer · 2013-04-09 14:16:10Z

1

json is a json object not an array, that is why you are getting the error. An array will be wrapped with in [ and ], and objects within { and }.

JSONObject uris = new JSONObject (json);

answered Apr 9, 2013 at 14:16

Arun P Johny

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1 Comment

exomen Over a year ago

Thanks a lot that helps!:) Sorry that can't make thumb up, not enough reputation.

Jeyvison · Accepted Answer · 2013-04-09 14:17:08Z

0

Instead of JSONArray you must use JSONObject.

JSONObject uris = new JSONObject(json);

answered Apr 9, 2013 at 14:17

Jeyvison

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Comments

Vivek Bajpai · Accepted Answer · 2013-04-09 14:17:28Z

0

In your code just replace JSONArray to JSONobject

JSONObject uris = new JSONObject(json);

answered Apr 9, 2013 at 14:17

Vivek Bajpai

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1 Comment

exomen Over a year ago

Thanks a lot that helps!:) Sorry that can't make thumb up, not enough reputation.

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