Object Management in String Pool ofJava

Question

Hi i am working in java and want to know how String objects are created in the String pool and how they are managed.

So in the following example i am creating two Strings s and s1,so can anyone explain me how many Objects are created in LIne1?Also how many Objects are eligible for garbage collection in Line3?

  String s = "x" + "y";//Line 1
  String s1 = s;//Line 2
  s = null;//Line 3

AmitG · Accepted Answer · 2013-04-20 20:09:43Z

3

Only one object is created "xy" . compiler does it for optimization.

No object is eligible for garbage collection.

answered Apr 20, 2013 at 20:09

AmitG

10.6k5 gold badges33 silver badges55 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

JavaGeek Over a year ago

So Objects "x" and "y" will not get created in the pool?My understanding is(which might be wrong) three object will be created.

ddmps Over a year ago

@JavaGeek That will only happen if you force it to create a new object, with new String(string)

AmitG Over a year ago

No. Concatenation of many literals in single line will create single object. Compiler generates such optimized code which will end up with single object.

Dhruv Kapatel · Accepted Answer · 2019-05-11 21:12:06Z

0

It would create one object xy in the String constant pool area. As "x"+"y" would be evaluated during compilation. Additionally, garbage collector cannot access String constant pool area.

Reference: https://docs.oracle.com/javase/specs/jls/se7/html/jls-3.html#jls-3.10.5

edited May 11, 2019 at 21:12

answered May 10, 2019 at 15:04

Dhruv Kapatel

9133 gold badges14 silver badges27 bronze badges

Collectives™ on Stack Overflow

Object Management in String Pool ofJava

2 Answers 2

3 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

3 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related