Implementing a c-code loop in python

Question

I have a following loop in C:

for (i = 0, j = nvert-1; i < nvert; j = i++) {
//do something
}

I want to write this loop in python. I know that in Python the loop uses the range(start,end) format, so I think I should make this somehow as follows:

for i in range(0,nvert):
    for j in range(???):
        #do something

so my problems are with this:

how can I determine the range of j?
how can I do the j=i++ trick in python (so this loop would act the same as the C-loop above)?

how do you use the indexes? Often in Python, you can drop indexes and iterate over container's items directly e.g., instead of for (i = 0; i < n; ++i) a[i]; in C, you could write for item in a: item in Python. If you want a circular buffer; look at collections.deque() — jfs
– jfs, Commented May 2, 2013 at 8:09

jamylak · Accepted Answer · 2013-05-02 08:11:43Z

3

You don't need the second loop. You can simply include it into the loop:

j = nvert - 1
for i in range(0, nvert):
      # do stuff
      j = i

note that you can simply use range(nvert) instead of range(0, nvert)

edited May 2, 2013 at 8:11

jamylak

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answered May 2, 2013 at 7:49

Alex

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3 Comments

jamylak Over a year ago

@Blender I removed the semicolons, I think the 0, was just copying the OP

jamylak Over a year ago

as @Blender said you can tell OP range(nvert) is sufficient

Alex Over a year ago

@jamylak can you fix it? Actually, I am not a python programer.

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