PHP replace image content

Question

I'm not an expert with Regex, but I'm trying to convert an image URL to another and delete the height and width attributes...

$content = preg_replace('/src="([^"]*)(png|jpeg|jpg|gif|bmp)"/', 'src="http://www.mysite.com/thumb.php?url=$1&width=500&height=500"', $post_content);

$content = preg_replace( '/(width|height)=\"\d*\"\s/', "", $content);

echo $content;

Echoing the results doesn't give me an image extension:

<img src="http://www.mysite.com/thumb.php?url=http://www.mysite.com/wp-content/uploads/2013/02/image.&width=500&height=500" />

How can I do this?

src\s*=\s*"([^"]+\.(png|jpeg|jpg|gif|bmp))"

Ejaz
– Ejaz

2013-05-03 22:45:26 +00:00
Commented May 3, 2013 at 22:45 — Ejaz
– Ejaz, Commented May 3, 2013 at 22:45

Alex Shesterov · Accepted Answer · 2013-05-03 22:49:24Z

2

The $1 in your replacement-string refers to the first capturing group of your regex. In other words, the value of $1 is the character sequence matched by the first (...) in the regex.

The problem is, your first set of parentheses does not include file extensions - hence the missing filename extension in the result.

answered May 3, 2013 at 22:49

Alex Shesterov

27.8k14 gold badges91 silver badges110 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Alex Shesterov Over a year ago

@jlafforgue: I'm glad if I could help.

Collectives™ on Stack Overflow

PHP replace image content

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related