How to get a session variable work in java script function?

Question

It may look like a stupid question, but I went through various pages since 2 days, and didn't get to a solution by myself. So I made a session variable like this:

<?php
session_start();

$_SESSION['currentpage']="home";
?>

(I checked, it does make the variable and assign it right.)

Then I tried to use it as a parameter here:

<body onload="changepage($_SESSION['currentpage'])">

It doesn't pass the variable. I tried to put it into directly the function, like not as a parameter, but inside it, doesn't work either. I am seriously missing something here I bet. Can someone please help out? Thanks.

alexn · Accepted Answer · 2013-05-14 09:25:10Z

5

You are missing the PHP tags:

<body onload="changepage('<?php echo $_SESSION['currentpage']; ?>')">

answered May 14, 2013 at 9:25

alexn

59.2k14 gold badges114 silver badges146 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Stefan Candan Over a year ago

Or the shorter version, if your php.ini allows these: <?=$_SESSION['currentpage']; ?>

alexn Over a year ago

@StefanCandan Yeah, sure. That just comes down to personal preference, both works.

kgms_hylian Over a year ago

Oh my god. Thanks a lot, works now. Didn't know how to make it phpish there..:)

Hanky Panky · Accepted Answer · 2013-05-14 09:25:55Z

0

<body onload="changepage($_SESSION['currentpage'])">

Should be

<body onload="changepage('<?php echo $_SESSION['currentpage'];?>')">

answered May 14, 2013 at 9:25

Hanky Panky

46.9k9 gold badges76 silver badges95 bronze badges

Collectives™ on Stack Overflow

How to get a session variable work in java script function?

2 Answers 2

3 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

3 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related