Get PHP variable to check form

Question

I'm trying to get a php variable to send alert box to user:

    var filial = '<?php echo $counta; ?>';

    if (filial=='0') {  
        if (formObj.dropdown1.value=='') {  
            alert('Filial');  
            return false;  
        }  
    }

I think there is an error because alert is not showed...

Any tip to solve?

Thanks a lot

What is the output of your PHP script? What does your JavaScript console say? What is the value of filial at the if statement? Also, this probably isn't your issue, but use json_encode() when inserting values into JavaScript. — Brad
– Brad, Commented May 28, 2013 at 1:04

jspcal · Accepted Answer · 2013-05-28 01:04:22Z

1

view-source and see if filial is initialized... Then check console for any JS errors.

answered May 28, 2013 at 1:04

jspcal

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