Php image cannot displayed contains error

Question

<!DOCTYPE html>

<head>
    <title>Display Picture</title>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>
<body>
    <h1>A Picture from Our Collection</h1>
    <?php

    header("Content-type: image/jpeg");

    $id = $_GET["ident"];
    $pat = '/^[0-9]+$/';
    if(!preg_match($pat, $id)){
        exit; // broken image
    }
    $mysqli = new mysqli('localhost','root','9876543210','student13');
    $query = "select image from Picys where ident=$id";

    $result = $mysqli->query($query);

    $err = $mysqli->error;
    if(!empty($err)){
        exit;
    }

    $row = $result->fetch_array(MYSQLI_NUM);
    $bytes = $row[0];

    echo $bytes;
    ?>
    <hr />
    <h2>Tags</h2>
    <?php
    $stmt->close();
    $stmt = $mysqli->prepare("select Tagstr from PicyTags where Picid=?");
    $stmt->bind_param('s',$id);
    $stmt->execute();
    $stmt->bind_result($tag);
    $count = 0;
    while($stmt->fetch()){
        if($count==0){
            echo "<bold>Existing tags:</bold>";
        }
        $count++;
        echo "$tag<br />";
    }
    $mysqli->close();
    ?>
    <br />
    <h3>Add tag</h3>
    <p>You may add tags that characterize the contents of this picture.</p>
    <form action="./AddTag.php?ident=<?php echo $id ?>" method="POST">
        <fieldset>
            <legend>Your tag</legend>
                <input type="text" size="16" maxlength="16" />
        </fieldset>
        <input type="submit" value="Add Tag" />
    </form>
</body>

i cannot display the picture from my database. and where i wrong at? suppose correct ya

and from ADD TAG <h3> there nothing can show out. my output just a

<h1>A Picture from Our collection</h1>

In my browser ! Nothing come out

You're trying to use a image header on a HTML page, don't think that would work. Try making that php on a separated file and calling it from an image tag ? — Prix
– Prix, Commented Jun 8, 2013 at 17:30
@Prix. u mean i just delete the header right? and then how should i calling it? i mean in my php function — user2422414
– user2422414, Commented Jun 8, 2013 at 17:40
No, I meant you make another file specifically for printing the image with the header you are using and then on the above file u just call something like <img src="my_other_php_file_that_loads_the_image.php?imageId=1"> — Prix
– Prix, Commented Jun 8, 2013 at 18:38

Alexander Cogneau · Accepted Answer · 2013-06-08 17:35:21Z

2

You already send a response with the HTML tags and then you try to change the headers. The headers should be altered before anything is outputted to the browser.

answered Jun 8, 2013 at 17:35

Alexander Cogneau

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3 Comments

user2422414 Over a year ago

so how should i change it?

Alexander Cogneau Over a year ago

remove header("Content-type: image/jpeg");

user2422414 Over a year ago

after i delete it still display the A Picture from Our Collection. thats all nia

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