Regex: Get match from string into an object

Question

I want to fill an object with records from a string where it matches a rule. The rule is if it contains at least 3 dots with a space to the right(". . . ") then I extract the first text to the left, the text that I just selected and its length.

string strdata = "Nume. . . . . . .Data nasterii. . . . .Nr. . . .";
Regex rgx = new Regex(". . . ");//At least 3 dots ". . . "
foreach (Match match in rgx.Matches(strdata))
    lst.Add(new obj1{ Label = "?", Value = match.Groups[1].Value, Length = match.Groups[1].Length });

I want to achive:

enter image description here

Q: What pattern do I have to use ?

RandomWebGuy · Accepted Answer · 2013-07-02 20:54:18Z

1

You can use @"([\w\s]*)([\. ]{3,})" to achieve what I assume your trying to do.

That Regex will break out the text into the different groups and within those groups you will have the text value as well as the periods.

You can try it using this Regex Tester by inputing Nume. . . . . . .Data nasterii. . . . .Nr. . . . into the "Source" field and then entering in ([\w\s]*)([\. ]{3,}) into the "Pattern" field.

answered Jul 2, 2013 at 20:54

RandomWebGuy

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1 Comment

Misi Over a year ago

If I had a "/" in my label ( "Nume/Prenume. . . . . Data nasterii. . . " ) then I would have to modify the pattern so it would take the whole group. I changed the pattern to ([\w\s/]*)([\. ]{3,}) and it worked.

gilly3 · Accepted Answer · 2013-07-02 20:59:06Z

1

In a regular expression, . means match any character. To match a ., you need to escape it as \.. To match 2 or more instances of an expression, use {2,}.

string strdata = "Nume. . . . . . .Data nasterii. . . . .Nr. . . .";
Regex rgx = new Regex(@"(.+?)(\.( \.){2,})");//At least 3 dots ". . . "
foreach (Match match in rgx.Matches(strdata))
{
    lst.Add(new obj1
    {
        Label = match.Groups[1].Value,
        Value = match.Groups[2].Value,
        Length = match.Groups[2].Length
    });
}

edited Jul 2, 2013 at 20:59

answered Jul 2, 2013 at 20:49

gilly3

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4 Comments

gilly3 Over a year ago

@RandomWebGuy - Yep, I forgot the ? in the first group, and was looking at groups 0 and 1 instead of 1 and 2. My latest edit should work.

RandomWebGuy Over a year ago

Yeah. That seems to be closer. However it doesn't look like it's capturing all the periods right of the text? The first group for example only shows 4 periods? And then the next group has periods left of the text.

gilly3 Over a year ago

@RandomWebGuy - No, I don't see that. The Regex Tester you linked to shows the correct output.

RandomWebGuy Over a year ago

You're right. I must have been looking at a previous Regex before one of your updates. My apologizes.

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