batch expansion variable cannot be used in substring replace function

Question

im beginner, my task is something to do with renaming files in folder, first of all here is a piece of my code:-

setlocal enabledelayedexpansion
set tempLogDate=0
set g=0

for /r %targetStore% %%i IN (*2013*.*) do (
  set tempLogDate=9
  set g=!g:%tempLogDate%=!
)

the problem is variable %tempLogDate% value is 0 instead of 9, i know i need to use variable expansion(which i have) but i cant replace code "set g=!g:%tempLogDate%.rar=!" to "set g=!g:!tempLogDate!.rar=!", i try escape character but no result, guys pls help me..thanks in advance

before that, here is original code of string replacement that i refer to @echo off set string=This is my string to work with. set string=%string:to work with.=% echo %string% Output = This is my string base on it, i need to initialize value "to work with." into string variable since i need to use it in loop, so thats the mess, — paiseha
– paiseha, Commented Jul 15, 2013 at 7:46

Endoro · Accepted Answer · 2013-07-15 07:49:13Z

3

Please look for delayed expansion, setlocal /? and endlocal /?. Example:

@ECHO OFF &setlocal enabledelayedexpansion
set "tempLogDate=0"
set "g=0"

for /r %targetStore% %%i IN (*2013*.*) do (
  set "tempLogDate=9"
  CALL SET "g=%%g:!tempLogDate!=%%"
)

answered Jul 15, 2013 at 7:49

Endoro

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1 Comment

paiseha Over a year ago

wah you are batch GODLIKE, this is second time u solved my problem with very specific answer, many thanks, ~god bless u @Endoro~

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