Convert JsonObject to String

Question

{
    "data": 
    {
        "map":
        {
            "allowNestedValues": true,
            "create": "2012-12-11 15:16:13",
            "title": "test201212110004",
            "transitions": []
        }
    },
    "msg": "success",
    "code": "0"
}

Above is a JsonObject, the data is a JsonObject.

How to convert it to a String like "msg":"success" as you know, i can't directly add a double quotes outside data's value.

I can't get it... Could you rephrase and give (even non-working) code snippets illustrating what you're attempting to do? — sp00m
– sp00m, Commented Jul 15, 2013 at 9:56
You can add doublequotes with a backslash \" if that´s what you want. Please add your problem/question! — Benjamin Schwalb
– Benjamin Schwalb, Commented Jul 15, 2013 at 9:58
Is that an instance of org.json.JSONObject? If it is, you can simply call toString() method of JSONObject to get JSON text of theJSONObject. — Stanley
– Stanley, Commented Jul 15, 2013 at 10:01
It looks like what people who land here 3+ years later are finding useful is not at all related to what was asked. And it also looks like the question is long past help at getting clarified. I believe the original question was that @JayZhang wanted to flatten the object, such that data was a string representation of its inner json value. It seems no one answered how to do that. Doing so years later would be unlikely to have any value to others. People are landing from searching for converting json to a string and getting mired in a confused Q&A session best deleted. — dlamblin
– dlamblin, Commented Sep 26, 2017 at 4:19

Archmede · Accepted Answer · 2023-07-17 19:45:01Z

218

There is a built-in method to convert a JSONObject to a String. Why don't you use that:

JSONObject json = new JSONObject();

json.toString();

edited Jul 17, 2023 at 19:45

Archmede

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answered Jul 15, 2013 at 10:01

Tanu Garg

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6 Comments

Jay Zhang Over a year ago

{ "data": "{ "map": { "allowNestedValues": true, "pdId": 168543, "source": "" } }", "msg": "success", "code": "0" }

Onkar Musale Over a year ago

i'm getting \ \ \ slashes in response string. how to convert json object without getting \ \ \ slashes

Tanu Garg Over a year ago

@Onkar share your string sample along with code snippet.

Onkar Musale Over a year ago

similar to this thread. but unable to find answer. stackoverflow.com/q/16563579/8098322

Tanu Garg Over a year ago

{"date":"2013/5/15"}. Are u using import org.json.JSONObject; its working fine for me. Share your exact sample. JSONObject json = new JSONObject(); try { json.put("date", "2013/5/15"); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println(json.toString());

|

sureshtechi · Accepted Answer · 2022-08-24 04:27:08Z

27

You can use:

JSONObject jsonObject = new JSONObject();
jsonObject.toString();

And if you want to get a specific value, you can use:

jsonObject.getString("msg");

or Integer value

jsonObject.getInt("codeNum");

For long Integers

jsonObject.getLong("longNum");

edited Aug 24, 2022 at 4:27

sureshtechi

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answered Apr 18, 2018 at 1:28

Janiel Mac

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1 Comment

User1 Over a year ago

It is better to use jsonObject.optString("msg") and jsonObject.optInt("codeNum") because if you use getString() or getInt() and the msg or codeNum values are null it'll throw and error and stop the program. Only difference with the methods I have mentioned is they won't throw an error if the values are null.

Ruchira Gayan Ranaweera · Accepted Answer · 2013-07-15 10:01:40Z

9

you can use

JsonObject.getString("msg");

answered Jul 15, 2013 at 10:01

Ruchira Gayan Ranaweera

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Comments

Naveen Kumar · Accepted Answer · 2019-06-19 09:06:33Z

5

You can try Gson convertor, to get the exact conversion like json.stringify

val jsonString:String = jsonObject.toString()
val gson:Gson = GsonBuilder().setPrettyPrinting().create()
val json:JsonElement = gson.fromJson(jsonString,JsonElement.class)
val jsonInString:String= gson.toJson(json)
println(jsonInString)

edited Jun 19, 2019 at 9:06

answered May 18, 2019 at 12:57

Naveen Kumar

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Comments

Tomas Kraus · Accepted Answer · 2021-05-20 10:45:13Z

4

JsonObject seems to be JSON-P API. If this is true, I would use JsonWritter to write JsonValue into StringWriter:

    JsonObjectBuilder pokemonBuilder = Json.createObjectBuilder();
    pokemonBuilder.add("name", "Pikachu");
    pokemonBuilder.add("type", "electric");
    pokemonBuilder.add("cp", 827);
    pokemonBuilder.add("evolve", true);
    JsonObject pokemon = pokemonBuilder.build();
    StringWriter sw = new StringWriter(128);
    try (JsonWriter jw = Json.createWriter(sw)) {
        jw.write(pokemon);
    }
    String pokemonStr = sw.toString();

answered May 20, 2021 at 10:45

Tomas Kraus

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Comments

OverZealous · Accepted Answer · 2016-02-16 14:25:35Z

3

Add a double quotes outside the brackets and replace double quotes inside the {} with \"

So: "{\"data\":{..... }"

edited Feb 16, 2016 at 14:25

OverZealous

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answered Feb 16, 2016 at 13:48

NargesooTv

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Comments

Arman · Accepted Answer · 2022-02-20 08:52:31Z

2

Use This :

JSONObject json = new JSONObject();
JSONObject.valueToString(json.toString());

answered Feb 20, 2022 at 8:52

Arman

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1 Comment

Elikill58 Over a year ago

JsonObject =/= JSONObject

Fazal Haroon · Accepted Answer · 2022-10-26 15:19:53Z

Example of Model

public class Person {
    private String name;
    private String age;
// setter and getter
// toString method
}

Example of Service method

public String getPerson() {
        JSONObject returnObj = new JSONObject();
        Person person = new Person();
        person.setAge("24");
        person.setName("Fazal");
        returnObj.put("age", person.getAge());
        returnObj.put("name", person.getName());
        return returnObj.toString();
    }

Json in java dependency needed

<!-- https://mvnrepository.com/artifact/org.json/json -->
<dependency>
    <groupId>org.json</groupId>
    <artifactId>json</artifactId>
    <version>{New_Version}</version>
</dependency>

You will get this type of JSON result

Hakan Anlamaz · Accepted Answer · 2017-04-13 10:57:50Z

0

JSONObject metadata = (JSONObject) data.get("map"); //for example
String jsonString = metadata.**toJSONString()**;

answered Apr 13, 2017 at 10:57

Hakan Anlamaz

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1 Comment

Hakan Anlamaz Over a year ago

JSONObject json= (JSONObject) JSONValue.parse(jsonData); JSONObject data = (JSONObject) json.get("data"); After you have parsed the json data, you need to access the data object later get "map" data to json string.

vitalinvent · Accepted Answer · 2021-12-08 11:52:36Z

0

just use ObjectMapper

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(SerializationFeature.FAIL_ON_EMPTY_BEANS,false);
//here more config opts...
Car car = new Car("yellow", "renault");
objectMapper.writeValue(new File("target/car.json"), car);
String carAsString = objectMapper.writeValueAsString(car);

edited Dec 8, 2021 at 11:52

answered Dec 8, 2021 at 11:46

vitalinvent

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Comments

score 0 · Accepted Answer · 2022-09-09 09:08:03Z

0

JSONObject data = (JSONObject) data.get("map"); 
 //for example
String jsonString = data.toJSONString();

edited Sep 9, 2022 at 9:08

answered Sep 9, 2022 at 8:55

user6437920

Comments

pshetty · Accepted Answer · 2016-12-06 15:02:25Z

-2

     This should get all the values from the above JsonObject  
     System.out.println(jsonObj.get("msg"));
     System.out.println(jsonObj.get("code"));

     JsonObject obj= jsonObj.get("data").getAsJsonObject().get("map").getAsJsonObject();
     System.out.println(obj.get("allowNestedValues"));
     System.out.println(obj.get("create"));
     System.out.println(obj.get("title"));
     System.out.println(obj.get("transitions"));

answered Dec 6, 2016 at 15:02

pshetty

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1 Comment

ralfe Over a year ago

this doesn't answer the question.

Kavitha yadav · Accepted Answer · 2017-12-15 12:33:01Z

-2

You can use reliable library GSON

private static final Type DATA_TYPE_JSON = 
        new TypeToken<JSONObject>() {}.getType();           
JSONObject orderJSON = new JSONObject();
orderJSON.put("noOfLayers", "2");
orderJSON.put("baseMaterial", "mat");
System.out.println("JSON == "+orderJSON.toString());
String dataAsJson = new Gson().toJson(orderJSON, DATA_TYPE_JSON);
System.out.println("Value of dataAsJson == "+dataAsJson.toString());
String data = new Gson().toJson(dataAsJson);
System.out.println("Value of jsonString == "+data.toString());

answered Dec 15, 2017 at 12:33

Kavitha yadav

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Comments

Manojkanth · Accepted Answer · 2017-06-30 08:16:01Z

-5

 var data= {"data": {"map":{"allowNestedValues": true,"create": "2012-12-11 15:16:13","title": "test201212110004","transitions": []}},"msg": "success","code": "0"}

o/p:

Object {data: Object, msg: "success", code: "0"}

Use JSON.stringify to convert entire data into string like below

var stringData = JSON.stringify(data);

o/p:

"{"data":{"map":{"allowNestedValues":true,"create":"2012-12-11 15:16:13","title":"test201212110004","transitions":[]}},"msg":"success","code":"0"}"

Use JSON.parse to convert entire string object into JSON Object like below

var orgdata = JSON.parse(stringData);

o/p:

Object {data: Object, msg: "success", code: "0"}

edited Jun 30, 2017 at 8:16

Manojkanth

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answered Apr 17, 2017 at 14:22

Raghava

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Comments

Vivek Adhikari · Accepted Answer · 2015-12-11 07:42:48Z

-7

I think you need this :

Suppose you have Sample JSON like this :

{"ParamOne":"InnerParamOne":"InnerParamOneValue","InnerParamTwo":"InnerParamTwoValue","InnerParamThree":"InnerParamThreeValue","InnerParamFour":"InnerParamFourValue","InnerParamFive":"InnerParamFiveValue"}}

Converted to String :

String response = {\"ParamOne\":{\"InnerParamOne\":\"InnerParamOneValue\",\"InnerParamTwo\":\"InnerParamTwoValue\",\"InnerParamThree\":\"InnerParamThreeValue\",\"InnerParamFour\":\"InnerParamFourValue\",\"InnerParamFive\":\"InnerParamFiveValue\"}} ;

Just replace " by \"

edited Dec 11, 2015 at 7:42

user5498596

answered Aug 21, 2015 at 5:39

Vivek Adhikari

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