You can use Pattern and Matcher like so:
public static void main(String[] args) throws Exception {
final String[] values = {"DBValue0", "DBValue1", "DBValue2", "DBValue3", "DBValue4", "DBValue5", "DBValue6", "DBValue7", "DBValue8", "DBValue9", "DBValue10"};
final String originaltext = "This is 4, This is 2, This is 7";
final Pattern pattern = Pattern.compile("(?<=This is )\\d++");
final Matcher matcher = pattern.matcher(originaltext);
final StringBuffer sb = new StringBuffer();
while (matcher.find()) {
System.out.println(matcher.group());
final int index = Integer.parseInt(matcher.group());
matcher.appendReplacement(sb, values[index]);
}
matcher.appendTail(sb);
System.out.println(sb);
}
Output:
4
2
7
This is DBValue4, This is DBValue2, This is DBValue7
EDIT
Further to the OP's comment is seems that the OP needs to replace Strings of the form {name, index} where "name" is the name of an array and "index" is the index of an element in that array.
This is easily achieved by Mapping the arrays to their names using a Map<String, String[]> and then using a Pattern that captures first the name then the index.
public static void main(String[] args) throws Exception {
final String[] companies = {"Company1", "Company2", "Company3"};
final String[] names = {"Alice", "Bob", "Eve"};
final String originaltext = "This is {company, 0}, This is {name, 1}, This is {name, 2}";
final Map<String, String[]> values = new HashMap<>();
values.put("company", companies);
values.put("name", names);
final Pattern pattern = Pattern.compile("\\{([^,]++),\\s*+(\\d++)}");
final Matcher matcher = pattern.matcher(originaltext);
final StringBuffer sb = new StringBuffer();
while (matcher.find()) {
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
final int index = Integer.parseInt(matcher.group(2));
matcher.appendReplacement(sb, values.get(matcher.group(1))[index]);
}
matcher.appendTail(sb);
System.out.println(sb);
}
Output:
company
0
name
1
name
2
This is Company1, This is Bob, This is Eve
PatternandMatcher