jQuery dropdown if selected value

Question

I have the following code:

$('[name^=business_] option:selected').each(function(){
    var bus = $(this).text();
    alert(bus);
});

This brings back the selected values of all the dropdowns with the name beginning with business_ - this is fine.

What I need is, if none of the dropdowns have a selected value equal to or higher than 1 then return an alert.

But I cannot fathom how to achieve this, I've tried looking at adding the values together but no joy - any pointers welcome.

Jason P · Accepted Answer · 2013-07-31 20:27:20Z

3

Iterate over the dropdowns, and once you find one with a value greater than one, set a flag and break the loop.

var foundOne = false;
$('[name^=business_] option:selected').each(function() {
    if ($(this).val() >= 1) {
        foundOne = true;
        return false;
    }
});

if (!foundOne) {
    alert('No selected options had a value of 1 or higher'); 
}

edited Jul 31, 2013 at 20:27

answered Jul 31, 2013 at 20:18

Jason P

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3 Comments

Homer_J Over a year ago

Thanks for the reply but not quite there - what I need is if all 10 dropdowns are not equal to or greater than 1 then an alert needs to happen - not at each iteration. Does that make sense?

Jason P Over a year ago

I think you may be confused on the return false;. That is returning from the anonymous function within each(). It doesn't return from whatever validation function this is all contained in. You can return false; from each() to break the loop and stop iterating.

Homer_J Over a year ago

THANK YOU for the update - a stonking piece of code that works perfectly. That has had me stumped for hours!!!

Dom · Accepted Answer · 2013-07-31 20:31:18Z

0

Why not use .filter() then check the length:

   var arr = $('select option:selected').filter(function(){
       if(this.value > 1)
           return this; 
    });

    if(arr.length) // arr.length > 0 also valid
        alert('yes');

DEMO: http://jsfiddle.net/vaTVX/1/

answered Jul 31, 2013 at 20:31

Dom

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1 Comment

Jason P Over a year ago

Because we only need one item to meet the criteria. filter() will iterate the entire list even when the first item meets the success condition.

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