python simple json error ? or API error?

Question

I have these code here http://pastebin.com/YHpZQ9Z9

After a few interval randomly, the error pops out and I cannot debug on what is causing the problem, can any professional help me ?

I encounter these error:

Traceback (most recent call last):

run()    

weather_Connection(intervalone)

response = get_response(conn, url)

return json.loads(data)

return _default_decoder.decode(s)

obj, end = self.raw_decode(s)

return self.scan_once(s, idx=_w(s, idx).end())

return _scan_once(string, idx)

raise JSONDecodeError(errmsg, string, idx)
simplejson.scanner.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

DhruvPathak · Accepted Answer · 2013-08-05 08:10:39Z

1

Your url is probably returning an invalid json, it returns 502 status intermitttently

"https://api.forecast.io/forecast/59ff8cb7661d231f2967c2663c0a3bdc/1.37871,103.848808"

edited Aug 5, 2013 at 8:10

answered Aug 5, 2013 at 7:57

DhruvPathak

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5 Comments

user2556720 Over a year ago

Any idea how can i fix this ? The website is sometimes unstable and is returning invalid key, but after a few refreshes it work. How can I counter measure this ?

DhruvPathak Over a year ago

You can use memcached to store valid responses for few minutes, the forecasts do not change in that time, and that would make your app faster as ewll.

adamr Over a year ago

Instead of httplib I prefer to use requests. docs.python-requests.org/en/latest

user2556720 Over a year ago

I don't get it when <------- # HOST NOT USED HERE ? How to put host there?

DhruvPathak Over a year ago

@Helpme, that code was correct, ignore my comment. The only error is 502 being returned from the api, you have to check the status and proceed accordingly.

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