REST call Javascript

Question

How do I make a call to a REST Api with Javascript (or ajax or jquery)?

curl -v -X PUT -H "Content-Type: application/json" -H "Accept: application/json" -X PUT --user user:password http://url -d "{\"name\": \"Marcus0.2\",\"start\": 1361381326000,\"end\": 1361640526000}"

I need help converting this to a useable ajax call. Thanks

$.ajax({
    type: 'put',
    url: 'https://this.is.my/url',
    dataType: 'json',
    data: { \"name\": \"Marcus0.3\" , \"start\": 500000 , \"end\": 1361640526000 }
    });

This code does not work [not sure why]. Also, 'https://this.is.my/url' is just short for the longer url, which I don't want to post online

Hmmm. Are you set against using jQuery? jQ sure makes it easy via $.ajax(). — Jonathan M
– Jonathan M, Commented Aug 5, 2013 at 21:03
I did, but I struggling to get it to work. I'll update the question with my current code — IdeoREX
– IdeoREX, Commented Aug 5, 2013 at 21:06

Brad · Accepted Answer · 2013-08-05 21:12:05Z

2

No need to add escaping to your data element... you can send a whole object and jQuery will take care of it for you.

$.ajax({
  type: 'put',
  url: 'https://this.is.my/url',
  dataType: 'json',
  data: {
    name: 'Marcus0.3', 
    start: 500000,
    end: 1361640526000 
  }
});

answered Aug 5, 2013 at 21:12

Brad

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2 Comments

IdeoREX Over a year ago

Followup question: This call returns a dictionary. How can I save/access this dictionary? thanks

Brad Over a year ago

@IdeoREX, $.ajax() returns a promise, which you can use to add a callback to handle when the request is done. This callback will get the data in an argument. $.ajax(/* ... */).done(function (data) { console.log(data); }); See the example near the bottom of the documentation page: api.jquery.com/jQuery.ajax

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