Scala pattern matching with function arguments

Question

I am a newbie in scala. I am trying to understand below lines of code:-

val word = "f"
val file = "resources/abc.dat"

val func: (String) => String = word match {
     case "f" => first
     case "s" => second
     case "t" => third
     case _ => default
}

def first(file: String) : String = {
     println("First" + file)
     "first"
}

def second(file: String) : String = {
     println("Second" + file)
     "second"
}

def default(file: String) : String = {
     println("Default" + file)
     "default"
}

What I understand so far is in func, word is matched with cases and particular function is called.But I don't understand how arguments are passed to each function call.

Any pointers will be of great help to me.

Thanks.

Vincenzo Maggio · Accepted Answer · 2013-08-11 17:34:06Z

4

Nope, you are NOT calling function in your pattern matching, you are just RETURNING a function , indeed the type of func is (String) => String, which you can abbreviate in String=>String.

You could then call it like func("ABCDE").

See this for a brief explanation on Scala types

answered Aug 11, 2013 at 17:34

Vincenzo Maggio

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1 Comment

neham Over a year ago

Thank you so much for clarification.I am able to understand the flow now.

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