Making a list in user-defined functions

Question

I'm trying to understand this error of:

  float object has no attribute a

Here is a simplified version of my code:

    def Apple():
             a = input("first: ")
             b = input("second: ")

             list1 = [0..a];
             list2 = [0..b];

             print list1, list2

Here is how the error is given

    >> Apple()
    >> AttributeError: 'float' object has no attribute 'a'

Not sure if this was introduced in posting the question or part of your actual code, but your second input has a typo — StephenTG
– StephenTG, Commented Aug 12, 2013 at 19:12
What are you looking to do? If you're looking to produce ranges, then that's not how it's done in Python. — Sukrit Kalra
– Sukrit Kalra, Commented Aug 12, 2013 at 19:12
Basically. I've been trying ways to make lists out of parameters inputted by the user, and doing things with numpy to those lists. and then printing the results. But, I just can't seem to make the lists. Where is the error, Stephen? — Niles Bernoulli
– Niles Bernoulli, Commented Aug 12, 2013 at 19:15
@NilesBernoulli What gave you the idea that [0..a] would make a list? — Waleed Khan
– Waleed Khan, Commented Aug 12, 2013 at 19:16
@NilesBernoulli I was just pointing out that one of your inputs was an inout. It has since been changed. Joran and Apero seem to have an idea what the overarching issue is. — StephenTG
– StephenTG, Commented Aug 12, 2013 at 19:17

Max Wallace · Accepted Answer · 2013-08-12 19:17:25Z

4

Since the poster asked about the error specifically:

I believe that in the line list1 = [0..a];

the python interpreter takes the expression 0..a, and parses it as the float 0. followed by a call to the a attribute of 0., which is usually what a dot means in that context.

As has been mentioned already, to create a range, use range(0, int(a)) instead.

answered Aug 12, 2013 at 19:17

Max Wallace

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Joran Beasley · Accepted Answer · 2013-08-12 19:13:57Z

3

range(int(a)) is what you want I think, not [0..a]

on a side note input is very dangerous in py2x since it evaluates the input

answered Aug 12, 2013 at 19:13

Joran Beasley

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4 Comments

Joran Beasley Over a year ago

not in python ... that is the notation in some other languages though

Joran Beasley Over a year ago

good catch ... (I assume he is using py2 which is why it worked)

Sukrit Kalra Over a year ago

In Python 3, you need to call list(...) too, since this would return a generator. :)

Joran Beasley Over a year ago

depending on if a generator will work for his needs ... a generator is often perferred (maybe I should have used xrange) .. but its moot since I am fairly confident he is using 2x

DevLounge · Accepted Answer · 2013-08-12 19:14:43Z

0

I guess you mean:

list1 = range(a)
list2 = range(b)

And why these ";" this is python, not javascript.

answered Aug 12, 2013 at 19:14

DevLounge

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