Warning: Invalid argument supplied for foreach() php wordpress

Question

I have this PHP code that produces a warning:

Warning: Invalid argument supplied for foreach() php wordpress

Here is the code:

<?php   
    $post_status1  = 'publish'; 
    $post_type1 = 'page';
    $featucat = "about";
    $featucount = "1";

    $my_query = new WP_Query('post_status='. $post_status1 .'&post_type='. $post_type1.'');  
    if ($my_query->have_posts()){
        while ($my_query->have_posts()) : $my_query->the_post();

            $front_values = get_post_custom_values('Homepage_Blog_01p', get_the_ID());
            foreach ( $front_values as $front_key => $result_value ) {
                if($result_value == 'about') {
?>

                    <div class="thewidgets">
                        <?php
                        $description_values = get_post_custom_values('Description_Field', get_the_ID());
                        foreach ( $description_values as $description_key => $description_value ) {
                            echo $description_value;

                        }
                        ?>
                        <a href="<?php the_permalink(); ?>" title="Read the whole post" class="rm">Read More</a>
                    </div>
    <?php } } endwhile; } ?>

Here is the full error:

Warning: Invalid argument supplied for foreach() in 
D:\PROGRAM FILES\wamp\www\westchester\wp-content\themes\
computerrepair\footer.php on line 22"

What am I doing wrong?

ceejayoz · Accepted Answer · 2013-08-18 20:02:44Z

1

$front_values is not an array if you're getting that. Check its contents, and if it's legitimately not an array at times (for example, if get_post_custom_values returns null when there aren't any results), account for it by wrapping the foreach in an if(is_array($front_values)) { conditional.

answered Aug 18, 2013 at 20:02

ceejayoz

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4 Comments

Jacky lou Over a year ago

thanks for the answer, base on what you said, I added if(is_array($front_values)) { that wraps foreach ( $front_values as $front_key => $result_value ) { if($result_value == 'homepage1') { and the error is gone but yet no content is showing :(

ceejayoz Over a year ago

If nothing is showing, get_post_custom_values('Homepage_Blog_01p', get_the_ID()) isn't returning anything. Check its output by print_r($front_values).

Jacky lou Over a year ago

yes, I tried print_r($front_values) it and nothing has been outputted so I could conclude that it isnt really returning anything, so what should I do to make it show? any idea?

Jacky lou Over a year ago

thank you! i already figured it out, thanks for the guidance :)

Eric Leschinski · Accepted Answer · 2014-08-11 18:03:13Z

0

How to reproduce this PHP warning:

Put this in a.php:

<?php
$skipper = "abcd";
foreach ($skipper as $item){       //warning happens on this line.
    print "ok";
}

?>

Prints:

eric@dev ~ $ php a.php
PHP Warning:  Invalid argument supplied for foreach() in 
/var/www/sandbox/eric/code/php/run06/a.php on line 3
PHP Stack trace:

The warning means exactly what it says. You passed a parameter into the foreach structure which could not be evaluated in the foreach. Before the foreach loop, ensure that the first parameter is a structure that the foreach can handle.

answered Aug 11, 2014 at 18:03

Eric Leschinski

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Comments

Jai Prakash · Accepted Answer · 2021-07-26 16:15:46Z

0

<?php wp_head(); ?>

Add this code in the head tag. I think it will solve your warning - Warning: Invalid argument supplied for foreach() in C:\wamp64\www\development\wp-includes\script-loader.php on line 2652

answered Jul 26, 2021 at 16:15

Jai Prakash

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