Php redirect with variable

Question

I am trying to use

  header("Location: http://www.mysite.com/gamecode.php?gameid=$pw");

below is my code.

   <?php
header("Location: http://www.mysite.com/gamecode.php?gameid=$pw");
$con = mysqli_connect("localhost","placeholder","placeholder","placeholder");
 //or die ('unable to connect');

 // Check connection
 if (mysqli_connect_errno())
 {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }


 //create random table name

  $alpha = "abcdefghijklmnopqrstuvwxyz";

  $numeric = "0123456789";
  $special = ".-+=_,!@$#*%<>[]{}";
  $chars = "";

  if (isset($_POST['length'])){
  // if you want a form like above
  if (isset($_POST['alpha']) && $_POST['alpha'] == 'on')
    $chars .= $alpha;

if (isset($_POST['alpha_upper']) && $_POST['alpha_upper'] == 'on')
    $chars .= $alpha_upper;

if (isset($_POST['numeric']) && $_POST['numeric'] == 'on')
    $chars .= $numeric;

if (isset($_POST['special']) && $_POST['special'] == 'on')
    $chars .= $special;

$length = $_POST['length'];
}else{
// default [a-zA-Z0-9]{9}
$chars = $alpha . $numeric;
$length = 6;
 }
$len = strlen($chars);
$pw = '';

 for ($i=0;$i<$length;$i++)
    $pw .= substr($chars, rand(0, $len-1), 1);
  // the finished password
 $pw = str_shuffle($pw);
 //using the $pw variable for the table name
 $sql="CREATE TABLE `" . $pw . "` (
 PID INT NOT NULL AUTO_INCREMENT, 
 PRIMARY KEY(PID),
 Name CHAR(15))";
 if (mysqli_query($con,$sql))
 {
 echo "table was created";
  }
  else
 {
  echo "Did not create table";
 }



  mysqli_close($con);

above is the page i am trying to add the variable to the URL. I do get the the page redirect however it is not adding the header variable to the redirect as it should.

Change your ' to " as ' will treat $gmid as literal string, if you want a value there, either concatenate the string else use " — Mr. Alien
– Mr. Alien, Commented Aug 26, 2013 at 5:07

Sudhir Bastakoti · Accepted Answer · 2013-08-26 05:05:10Z

7

use double quotes instead of single quote, so change to:

header("Location: http://www.yoursite.com/new_page.php?gameid=$gmid");

or

header('Location: http://www.yoursite.com/new_page.php?gameid='.$gmid);

Double quotes, will evaluate variable values before producing the final output, which single quote does not.

answered Aug 26, 2013 at 5:05

Sudhir Bastakoti

100k15 gold badges163 silver badges169 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

st15jap Over a year ago

Thanks for your quick post! I wish I could select everyone's answer's you are all right!

GautamD31 · Accepted Answer · 2013-08-26 05:05:06Z

4

Try like

header('Location: http://www.yoursite.com/new_page.php?gameid='.$gmid);

You need to change the quotes before the variable or You can also try with double quotes like

header("Location: http://www.yoursite.com/new_page.php?gameid=$gmid");

answered Aug 26, 2013 at 5:05

GautamD31

28.8k10 gold badges66 silver badges86 bronze badges

Comments

user1890615 · Accepted Answer · 2013-08-26 05:04:37Z

4

try this:

header('Location: http://www.yoursite.com/new_page.php?gameid=' . $gmid);

answered Aug 26, 2013 at 5:04

user1890615

Comments

slash197 · Accepted Answer · 2013-08-26 05:05:00Z

3

Change your quotes to double quotes.

answered Aug 26, 2013 at 5:05

slash197

9,0246 gold badges44 silver badges71 bronze badges

1 Comment

Mr. Alien Over a year ago

Why do we change that? Lil explanation will be better here

itachi · Accepted Answer · 2013-08-26 05:07:31Z

1

header("Location: http://www.yoursite.com/new_page.php?gameid=$gmid");

see the quotes.... " instead of '.

answered Aug 26, 2013 at 5:07

itachi

6,3933 gold badges33 silver badges41 bronze badges

Comments

Charaf JRA · Accepted Answer · 2013-08-26 05:12:56Z

1

You have problem with quotes and double quotes: Change your line to this :

 header("Location: http://www.yoursite.com/new_page.php?gameid=$gmid");

or this:

 header("Location: http://www.yoursite.com/new_page.php?gameid=".$gmid);

If you do '$variable' , it will be interpreted as string and :

echo '$variable' ; will show $variable as output . But if you use "$variable" , echo will output value of this variable.

edited Aug 26, 2013 at 5:12

answered Aug 26, 2013 at 5:07

Charaf JRA

8,3551 gold badge36 silver badges45 bronze badges

6 Comments

st15jap Over a year ago

Does using the header require a session?

st15jap Over a year ago

ok. i am using the example above with the double quotes, it does redirect correctly but its not adding the variable. when i do a simple echo it does echo the variable to the page. (i have to comment out the header) any ideas what would do that?

st15jap Over a year ago

i was using $pw=$gmid but it wasnt working so i just went with the $pw.. do i need something else?

Charaf JRA Over a year ago

before header add this line $pw=1; and check if it appears in the link you are redirected to , if its ok,you have problem widh $pw, try to give it a value.

Charaf JRA Over a year ago

let us continue this discussion in chat

|

Collectives™ on Stack Overflow

Php redirect with variable

6 Answers 6

1 Comment

Comments

Comments

1 Comment

Comments

6 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

1 Comment

Comments

Comments

1 Comment

Comments

6 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related