Alright, so let's say I have a .bash file with this inside of it
lib.bash
#!/bin/bash
function hello_world {
echo "Hello World!"
}
That file won't be called on it's own, instead it'll be called via another bash file, i.e
Startup.bash
#!/bin/bash
bash lib.bash
hello_world
But, if I run Startup.bash I get the error: hello_world: command not found
What am I doing wrong, or is it not possible to do what I'm trying to do on bash.
You can use this command in your startup.bash:
source lib.bash
the source command runs the file in the current shell environment, unlike using bash lib.bash
(or . lib.bash) which creates a new, separate environment for that script (and only that script) and is why the function is not carried over.
(source)
why don't you call the function directly inside of the first script?
It would look something like this:
#!/bin/bash
function hello_world {
echo "Hello World!"
}
hello_world
If it is a simple script, shouldn't be a problem at all. Otherwise try the source command, like minerz029 suggested :)
See if this could be helpful to you as well:
source lib.bash