I have the following text:
some cool color #12eedd more cool colors #4567aa
I want that this string will be transformed to:
some cool color #{1} more cool colors #{2}
How is it possible to do it in Java (1.6)?
What I've found so far is the regex for color: #[0-9abcdef]{3,6}
You can use appendReplacement and appendTail from Matcher class
String data = "some cool color #12eedd more cool colors #4567aa";
StringBuffer sb = new StringBuffer();
Pattern p = Pattern.compile("#[0-9a-f]{3,6}", Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(data);
int i = 1;
while (m.find()) {
m.appendReplacement(sb, "#{" + i++ + "}");
}
m.appendTail(sb);//in case there is some text left after last match
String replaced = sb.toString();
System.out.println(replaced);
output:
some cool color #{1} more cool colors #{2}
A-F to the pattern.
appendReplacement method.You can try without regex as this
String str="some cool color #12eedd more cool colors #4567aa";
StringBuilder sb=new StringBuilder();
String[] arr=str.split(" ");
int count=1;
for(String i:arr){
if(i.charAt(0)=='#'){
sb.append("#{"+count+"} ");
count++;
}
else {
sb.append(i+" ");
}
}
System.out.println(sb.toString());
out put:
some cool color #{1} more cool colors #{2}
# in the string that isn't followed by a hexadecimal number?
i against the color regex patternWell may be this is not you are looking for but you have other option without using regex, this is simple with little bit complexion :)
StringBuilder q = new StringBuilder("some cool color #12eedd more cool colors #4567aa");
int i;
int j=1;
while(q.indexOf("#")>0){
q.replace(i=q.indexOf("#"),i+7, "${"+ j++ +"}");
}
String result = q.toString().replaceAll("\\$", "#");
System.out.println(result);
Output:
some cool color #{1} more cool colors #{2}
#[0-9abcdef]{3,6}But I don't know how I can iterate over string and replace the colors.[0-9a-f]instead of[0-9abcdef]...