Storing number of 1's in binary representation of an int array in another array

Question

I want to store the number of 1's in the binary representation of some integers given in an array in another corresponding array; following is the code I am writing; but it shows the error "Change type of 'arr' to 'int'" What's going wrong?

public static int[] arrange(int[] numbers){
String[] arr = new String[numbers.length];
for(int i =0;i<numbers.length;i++){
    arr[i]= Integer.toBinaryString(numbers[i]);
}
int[] a2 = new int[numbers.length];
for(int i =0;i<numbers.length;i++){
    a2[i]=Integer.bitCount(arr[i]);
}

arr is containing strings, but Integer.bitCount wants an int. — Oskar Kjellin
– Oskar Kjellin, Commented Sep 17, 2013 at 9:38

Debojit Saikia · Accepted Answer · 2013-09-17 09:44:38Z

1

You are passing a String to Integer.bitCount method:

a2[i]=Integer.bitCount(arr[i]);

But the method bitCount(int) is not applicable for the arguments (String). Change this assingment to pass int value to bitCount:

a2[i]=Integer.bitCount(Integer.parseInt(arr[i]));

answered Sep 17, 2013 at 9:44

Debojit Saikia

10.7k3 gold badges37 silver badges46 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Sajan Chandran · Accepted Answer · 2013-09-17 09:44:32Z

1

As per Integer documentation, method bitCount requires an int and a String,

Integer.bitCount(arr[i]);, arr[i] is String

answered Sep 17, 2013 at 9:44

Sajan Chandran

11.5k3 gold badges34 silver badges41 bronze badges

Collectives™ on Stack Overflow

Storing number of 1's in binary representation of an int array in another array

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related