"Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0" java error

Question

i get this error message when i try to break in 2 parts (with "break point" the character "@")

part_fixed

part_user

a secret key "final key" saved as string.

       service_codeEncrypted_key = new SecretKeySpec(service_codeEncrypted, 0, 8, "DES");


        System.out.println("");
        System.out.println("Secret code as secret key :" + service_codeEncrypted_key);
        System.out.println("");
        String final_key = "service_codeEncrypted_key";//key has the form xxx.xxx.xxx.xxx@yyyyy
        String[] parts = final_key.split("@") ;
        String part_fixed = parts[0]; // xxx.xxx.xxx.xxx
        String part_user = parts[1]; // yyyy
        System.out.println("");             
        System.out.println("Service Code decrypted : " + new String(service_codeDecrypted)); // Print the decrypted Text
        System.out.println("");
        // System.out.println("Code for the card : " + part_user); // Print the decrypted Text          
        System.out.println("Finish!!!"); // Print the decrypted Text
        System.out.println("-----------------------------------------------------------------------------------"); // Print the decrypted Text
        System.out.println("");
        System.out.println("");

The error as shown in the console in the following :

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 at JEncrytion.main(JEncrytion.java:182)

where line 182 is : String part_fixed = parts[0];

The acual key has the form xxx.xxx.xxxxxx.xxx@yyyyy, and i want all the x's in one part and all the y in the second one.

Any ideas?

why don't you print the length of the parts (System.out.println(parts.length);) before accessing the array elements to see how many elements are there? — Jiji
– Jiji, Commented Sep 25, 2013 at 9:45

Prabhakaran Ramaswamy · Accepted Answer · 2013-09-25 09:52:10Z

1

String final_key = "service_codeEncrypted_key"; // here is the problem

Replace with the following

String final_key = service_codeEncrypted_key;

and consider this one too

   String part_fixed ="";
   String part_user ="";
   if(parts!=null){
       part_fixed = parts[0]; // xxx.xxx.xxx.xxx
       part_user = parts[1]; // yyyy
   }

edited Sep 25, 2013 at 9:52

answered Sep 25, 2013 at 9:42

Prabhakaran Ramaswamy

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1 Comment

kiko77 Over a year ago

Thanx mate, that was actually the problem, which of course created another one (i was silly to thing that a secret key could be saved as a string so easily). Thanx again, silly error, i know.

Juned Ahsan · Accepted Answer · 2013-09-25 09:42:04Z

0

final_key (value = "service_codeEncrypted_key") string does not contain @ and hence the result of split will be an array of single element i.e the original string. So accesing the second element in that array as mentioned here:

parts[1];

will throw an ArrayIndexOutOfBoundsException

The logical problem in your code is that you wanted to assign the service_codeEncrypted_key variable to final_key but instead you did the string assignment. So as mentioned by Prabhakaran in his answer, replace this:

String final_key = "service_codeEncrypted_key";

with

String final_key = service_codeEncrypted_key;

answered Sep 25, 2013 at 9:42

Juned Ahsan

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kiko77 Over a year ago

Thanx Juned, just mentioned i save the name of the secter key as a string , and not the secret key itself!

Ketan Bhavsar · Accepted Answer · 2013-09-25 09:44:10Z

0

That is right your key doesn't contain '@' symbol.

You need to code something like this.

if(final_key.contains("@")){
String[] parts = final_key.split("@") ;
    String part_fixed = parts[0]; // xxx.xxx.xxx.xxx
    String part_user = parts[1]; // yyyy
}

answered Sep 25, 2013 at 9:44

Ketan Bhavsar

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Comments

aUserHimself · Accepted Answer · 2013-09-25 09:44:10Z

0

String final_key = "service_codeEncrypted_key";

doesn't contain the @ character and so the parts[] has no element.

Try to use

String[] parts = service_codeEncrypted_key.split("@");

answered Sep 25, 2013 at 9:44

aUserHimself

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1 Comment

kiko77 Over a year ago

Thanx a! Your proposal is totally in the right direction, i just get the JEncrytion.java:181: cannot find symbol symbol : method split(java.lang.String) location: interface javax.crypto.SecretKey String[] parts = service_codeEncrypted_key.split("@"); error, because (of course) this is a secret key and not a string. I will try to convert it first.

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