CakePHP create URL from request params

Question

Is there a function to generate the corresponding URL given the request object?

For example, if the request params values are:

params => array(
        'plugin' => 'plugin',
        'controller' => 'foo',
        'action' => 'bar',
        'named' => array(),
        'pass' => array()
    )
    data => array()
    query => array(
                'key' => 'val'
        )
)

Then, generate the URL:

http://domain.com/plugin/foo/bar?key=val

You forgot the CakePHP version again. Also it's always helpful to explain the actual problem you are trying to solve, that way it's easier to figure a proper solution. That being said: Router::reverse($cakeRequestObject, true). — ndm
– ndm, Commented Oct 5, 2013 at 16:58
The Router::reverse worked. If you could post an answer so I could mark it :) — chrony
– chrony, Commented Oct 6, 2013 at 16:06

ndm · Accepted Answer · 2013-10-06 18:04:33Z

4

Whether this fits your needs depends of course, but generally Router::reverse() is able to build a URL from a request object:

Router::reverse($cakeRequestObject, true)

It's much like Router::url(), but it will do all the dirty work for you like including the query values and removing unnecessary parameters.

answered Oct 6, 2013 at 18:04

ndm

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Comments

Lakhan · Accepted Answer · 2015-11-06 05:51:19Z

0

Just Use Router::reverse() like that way :

$url = Router::reverse($this->params);
echo $url;

answered Nov 6, 2015 at 5:51

Lakhan

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