Initializing a jagged array in c# gives index out of range exception

Question

field = new int[input.Width][][];

for (int x = 0; x < input.Width; x++)
{
       field[x] = new int[input.Height][];

       for (int y = 0; y < 3; y++)
       {
           field[x][y] = new int[3];
       }
}

For some reason the above code is giving me out of range exception but the following works fine:

field = new int[input.Width][][];

for (int x = 0; x < input.Width; x++)
{
       field[x] = new int[input.Height][];

}

for (int y = 0; y < input.Height; y++)
{

       for (int x = 0; x < input.Width; x++)
       {
            field[x][y] = new int[3];                   

            field[x][y][0] = random.Next(0, output.Width);
            field[x][y][1] = random.Next(0, output.Height);
            field[x][y][2] = MaskFunctions.DSCALE;

        }
 }

Can anyone point out what am i doing wrong?

Also: Is there a difference between out of range and out of bound exception?

the first has y < 3, the second has y < input.Height. Do those values differ? — ps2goat
– ps2goat, Commented Oct 10, 2013 at 23:22

p.s.w.g · Accepted Answer · 2013-10-10 23:20:26Z

4

Your inner loop goes from 0 to 3, instead of 0 to input.Height. This will produce an out of range exception when input.Height < 3.

You probably meant to do this:

field = new int[input.Width][][];

for (int x = 0; x < input.Width; x++)
{
       field[x] = new int[input.Height][];

       for (int y = 0; y < input.Height; y++)
       {
           field[x][y] = new int[3];
       }
}

answered Oct 10, 2013 at 23:20

p.s.w.g

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2 Comments

Ali Zahid Over a year ago

Thanks! it worked! can you also tell me if there is a difference between out of range and out of bound exception?

p.s.w.g Over a year ago

@AliZahid There's no difference, at least in this context. Some people just prefer to use different language. .NET calls it IndexOutOfRangeException but Java calls it an an ArrayIndexOutOfBoundsException. In either case, they mean essentially the same thing.

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