get the namespace prefix and namespace binding of an XML element

Question

For the following XML instance:

<foo:a xmlns:foo="http://foo"> <b> whatever </b>   </foo:a>

One can use the local-name(/*) and name(/*) XPath expressions to get a and foo:a respectively (as shown in this SO post).

Are there any XPath expressions to:

I have edited your title. Please see, "Should questions include “tags” in their titles?", where the consensus is "no, they should not". — John Saunders
– John Saunders, Commented Oct 11, 2013 at 18:43
@JohnSaunders re the backlashes, no my bad I copy-pasted the XML out of a String literal in code, have now fixed that. — Marcus Junius Brutus
– Marcus Junius Brutus, Commented Oct 11, 2013 at 18:47

BeniBela · Accepted Answer · 2013-10-11 20:12:03Z

2

You can use namespace-uri:

namespace-uri(/*)

answered Oct 11, 2013 at 20:12

BeniBela

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1 Comment

And as for the other question, the only way to get the prefix is to use name() and extract the part before the colon.

lschult2 · Accepted Answer · 2021-11-02 15:39:18Z

2

I've found this works to get the prefix (xpath 2.0):

prefix-from-QName(node-name())

answered Nov 2, 2021 at 15:39

lschult2

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