In perl I can define a bunch of variables in 1 line:
my value=0;
my (a,b,c)=value;
is there some similar C# way of doing the same? here is what I have:
const bool free = true;
bool t1,t2,t3;
private void Form1_Load(object sender, EventArgs e) {
//t1,t2,t3=free;
}
I believe you can do t1 = t2 = t3 = free; However, it really makes it much harder to read. I would not recommend it.
my (a,b,c)=value or similar constructs as may be found in Perl, Python, Ruby, or Scala which support decomposition during assignment. Rather the same value (e.g. the result of evaluating free) is assigned to all the variables (e.g. t1, t2, t3). With few exceptions (such as in a while or default-value construct) I find this behavior only of moderate use. In C#, t1 = t2 = t3 = value is equivalent to t1 = (t2 = (t3 = value)) as the assignment operator is rightward associative and evaluates to the value assigned but is otherwise not very special.
C# does not support full destructuring assignment. Thus, there is no C# equivalent of
my @v = (1,3,5);
my ($a,$b,$c) = @v;
However, as pointed out by @Guthwulf, in the case of a scalar you can write t1 = t2 = t3 = free and it will assign the same value to each element.
=(although thea=bexpression itself yields the value ofb). The equivalent is, therefore, multiple assignments.