How to call image url from directory using php

Question

I want to display the image and the image url of a directory
I found this code, but there is a dot before the filename.

<?php
$files = glob("./images/*.*");
for ($i=0; $i<count($files); $i++) {
    $image = $files[$i];
    print "<textarea>";
    print "http://" .$_SERVER['SERVER_NAME'].$image;
    print "</textarea>"."<br />";
    echo '<img src="'.$image .'" />'."<br /><br />";    
}
?>

the result will be like this :

<textarea>http://domain.com./images/filename.png<textarea>
<img src="./images/filename.png" />

please help to fix this. thanks.

Try reading this turorial w3schools.com/php/func_directory_readdir.asp To read files in a directory, you must used the mthod over there. — Juan Garcia
– Juan Garcia, Commented Oct 17, 2013 at 18:25

Josh Crozier · Accepted Answer · 2013-11-02 02:14:14Z

2

I solved the problem by using the following:

<?php
$files = glob("images/*.*");
for ($i=0; $i<count($files); $i++) {
    $image = $files[$i];
    echo '<img src="'.$image .'" />'."<br /><br />";   
    print "<textarea>";
    print "http://" .$_SERVER['SERVER_NAME'].$image;
    print "</textarea>"."<br /><br /><br />"; 
}
?>

edited Nov 2, 2013 at 2:14

Josh Crozier

242k56 gold badges401 silver badges316 bronze badges

answered Oct 18, 2013 at 6:45

Rudi tabuti

232 silver badges6 bronze badges

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