Get json value without string prefix

Question

I have a json like this:

var x = {"foo:bar":"xyz"};

I can get xyz by call x["foo:bar"] but is there anyway to get xzy by calling just bar and remove the foo prefix? something like x["bar"]? The json is converted from xml with namespace like that, I can't change it. Thanks

What does "just def" mean? Who creates the json - do you? If it's you, just follow @JustinWood advice and modify how you output it. — random_user_name
– random_user_name, Commented Oct 22, 2013 at 16:35
The json is converted from xml with namespace like that, I can't change it :( — Duc
– Duc, Commented Oct 22, 2013 at 16:40

MrCode · Accepted Answer · 2013-10-22 16:41:59Z

2

You can iterate over the property names and remove the prefix:

function removePrefix(x){
    var temp = {};
    for(var key in x){
        temp[key.substr(key.indexOf(':')+1)] = x[key];
    }
    return temp;
}

var x = {"foo:bar":"xyz"};

x = removePrefix(x);

console.log( x['bar'] ); // xzy
console.log( x.bar ); // xyz

answered Oct 22, 2013 at 16:41

MrCode

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1 Comment

Duc Over a year ago

what if the structure of the json is more complex, eg: it has child and array in it?

SidOfc · Accepted Answer · 2013-10-22 16:36:57Z

0

You would create a JSON string which would look like this:

var x = {"foo":"xyz"};

your current key: "foo:bar" does not have any special meaning in JSON, it's part of the key.

answered Oct 22, 2013 at 16:36

SidOfc

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