Creating sequential sublists from a list

Question

I'm new here and to programming as well.

I don't know if I put the question right, but I have been trying to generate sublists from a list.

i.e

say if L = range(5), generate sublists from L as such [[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]].

Kindly assist. Thanks.

score 1 · Accepted Answer · 2013-10-27 23:48:56Z

1

Look at this:

>>> # Note this is for Python 2.x.
>>> def func(lst):
...     return map(range, xrange(len(lst)+1))
...
>>> L = range(5)
>>> func(L)
[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]]
>>>

edited Oct 27, 2013 at 23:48

answered Oct 27, 2013 at 23:00

user2555451

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praba230890 · Accepted Answer · 2013-10-29 22:42:34Z

0

You can also generate the sublists you've asked for by using the below for loop.

>>> L = range(5)
>>> l = []
>>> for i in range(len(L)+1):
        l.append([j for j in range(i)])
>>> l
[[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]]

Also you can create the sublists without an empty sublist as the starting sublist through the code:

>>> i = list(range(5))
>>> [i[:k+1] for k in i]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]]

answered Oct 29, 2013 at 22:42

praba230890

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