I have a list like
L=[[w,['0','0']],[r,['1']]]
I want to print it as
w = 00
r = 1
for getting this I tried like
for k in range(1,len(tab[0]))
print L[0][k][0],"=",(L[0][k][1])
but it prints like
w = ['0','0']
r = ['1']
can anyone help me? thanx in advance
In [5]: L=[['w',['0','0']],['r',['1']]]
In [6]: L1 = [item for item in L]
In [7]: L1
Out[7]: [['w', ['0', '0']], ['r', ['1']]]
In [8]: ['%s=%s' % (item[0], ''.join(item[1])) for item in L1]
Out[8]: ['w=00', 'r=1']
If the question is how do I convert ['0', '0'] to 00 then you may use join
for k in range(1,len(tab[0]))
print L[0][k][0],"=", ''.join((L[0][k][1]))
I don't fully understand the for loop (because I don't know what tab is) but to get string representation of a list, use join
Your list is wrong. Unless w and r are predefined variables, it should read as:
L=[['w',['0','0']],['r',['1']]]
In that case, the following will achieve the result: for item in L:
print(item[0], ''.join(item[1]))
Just use a simple for-loop with string formatting:
L = [['w', ['0','0']], ['r',['1']]]
for item in L:
print '{} = {}'.format(item[0], ''.join(item[1]))
What ''.join() does it joins every item in the list separated by the '' (i.e nothing). So:
['0', '0'] --> '00'
Go with this..
L=[[w,['0','0']],[r,['1']]]
for item in L:
print item[0], '=', ''.join(item[1])
Ans:
w = 00
r = 1
