Getting arrayindexoutofbounds when reading from file

Question

I have this small problem of mine, where I would be getting arrayindexoutofboundsexception when trying to read from file. I don't know of a better or more detailed way of explaining it, so I will paste the code and the error below. This is all in the mainmethod of my program.

    File fila;
    String[] innlesningsarray=new String[500];

    try{
        Scanner innFil=new Scanner(new File("/uio/hume/student-u77/makrist/Downloads/akronymer.txt"));

        while(innFil.hasNext()){
        for(int i=0; i<500; i++){

        // String innLest=br.nextLine();
            innlesningsarray=innFil.nextLine().split("\t");
            System.out.println(innlesningsarray[i]);
            System.out.println(innFil.nextLine());
        }
        System.out.println("test");
        }
        System.out.println("Test2");

    } catch(Exception e){
        System.out.print(e);
    }
    }
}

After this part I have an object of Acronyms and stuff, but no errors there...

The error:

AA Auto Answer

AAB All-to-All Broadcast

java.lang.ArrayIndexOutOfBoundsException: 1

Instead of print(e) you should write e.printStackTrace(). This will print a lot of useful information about the exception. — Roland Illig
– Roland Illig, Commented Nov 13, 2013 at 9:33
The posted code is not correct, but I don't see how it can result in an IOOBE. That exception comes from elsewhere (or possibly a different version/build of the code). — user2864740
– user2864740, Commented Nov 13, 2013 at 9:34

Joetjah · Accepted Answer · 2013-11-13 09:58:11Z

2

You do nextLine() twice in the loop. This will read 2 lines in your file.

while(innFil.hasNext()) can return true if you have 1 line left. Next thing you do is reading 2 lines in that while-loop. Since there is only 1 line left, you'll get your exception.

You have it placed in a for-loop as well. That means you do 500*2 times the readLine() method, while you only check for 1 line.

Try the following:

try{
    Scanner innFil=new Scanner(new File("/uio/hume/student-u77/makrist/Downloads/akronymer.txt"));

    while(innFil.hasNext()){
        for(int i=0; i<500; i++){
            String theReadLine = innFil.nextLine();
            innlesningsarray=theReadLine.split("\t");
            System.out.println(innlesningsarray[i]);
            System.out.println(theReadLine);
        }
        System.out.println("test");
    }
    System.out.println("Test2");

    } catch(Exception e){
        System.out.print(e.printStackTrace);
    }
}

This solves a possible error with the nextLine() method. You should be sure innlesningsarray actually has 500 or more entries, else you will receive your exception. Make sure that your akronymer.txt file has the string \t 500 or more times in it!

I also changed your catch-code. Instead of print(e) you should write e.printStackTrace(). This will print a lot of useful information about the exception. Thanks to Roland Illig for that comment!

edited Nov 13, 2013 at 9:58

answered Nov 13, 2013 at 9:28

Joetjah

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5 Comments

Makri Over a year ago

Where? O.O One is commented out and the other is a printline. This happened before I put in the printline as well. The array has 500 spaces, and the txt-file is long

Joetjah Over a year ago

If you place it in a printline, it still reads the line and puts the marker after that line.

user2864740 Over a year ago

I don't see how this addresses the IOOBE, since i is independent of nextLine.

Joetjah Over a year ago

As above user stated, this solves a possible error with the nextLine() method. You should be sure innlesningsarray actually has 500 or more entries, else you will receive your exception.

Makri Over a year ago

Figured it out. Thanks

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