Back again with another question.
The file I have right now is of the following format:
1234,
1234,
1-23-4
I would like to do two things with this file.
First, remove the - characters in the third line. Therefore, 1-23-4 ==> 1234.
Second, I would like to make it all print in one line.
The final result should look like:
1234,1234,1234
Is this possible using line commands in a script? Kindly advise.
Thank you in advance for your time and help.
With tr:
$ tr -d '\n-' < a | sed 's/$/\n/'
1234,1234,1234
To remove the hyphens:
$ tr -d '-' < file
1234,
1234,
1234
And the same applies for the new lines with \n.
As we are removing all new lines, it will miss the finishing one. To recover it, we use sed.
$prompt tr -d '\n-' < a
1234,1234,1234$prompt
$ tr -d '\n-' < a | sed 's/$/\n/'
1234,1234,1234
Thanks fedorqui.I tried this. I replaced file with my file name but it is not creating a new file with the final format for me. Sorry i think I should have mentioned this in the question. My bad.
No problem. You just need to redirect it:
$ tr -d '\n-' < a | sed 's/$/\n/' > new_file
$ cat new_file
1234,1234,1234
sed writing it back. By the way, congrats for being 300K, that's so big :)(gnu) awk:
awk -v RS="\0" 'gsub(/[\n-]/,"")' file
test
kent$ echo "1234,
1234,
1-23-4"|awk -v RS="\0" 'gsub(/[\n-]/,"")'
1234,1234,1234
tr was a good one.
Anotherway in perl:
perl -pne 's/[-\n]//g' your_file
-n-> this will act as a while loop for each line in the file.
-e-> the thing after this is nothing but the expression which will act on each an every line.
-p-> print each line after the expression is executed on each line.
s/search/replace/g
s/ search for either a newline or "-"/ replace with empty character/g-for all occurences in the line.
