I'm trying to write a servlet which will read (download) file from a remote location and simply send it as response, acting more-or-less like a proxy to hide the actual file from getting downloaded. I'm from a PHP background where I can do it as simply as calling file_get_contents.
Any handy way to achieve this goal using servlet/jsp?
Thanks
How about this one? FileUtils (Commons IO 2.5-SNAPSHOT API)
example /src_directory_path/ is mount directory of remote server.
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
resp.setContentType("application/octet-stream");
resp.setHeader("Content-Disposition", "filename=\"hoge.txt\"");
File srcFile = new File("/src_directory_path/hoge.txt");
FileUtils.copyFile(srcFile, resp.getOutputStream());
}
Was this by any chance what you wanted to hear?
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
InputStream in = new URL( "http://remote.file.url" ).openStream();
IOUtils.copy(in, response.getOutputStream());
}
resp.setHeader("Content-Disposition", "attachment; filename=\"hoge.txt\"")int BUFF_SIZE = 1024;
byte[] buffer = new byte[BUFF_SIZE];
File fileMp3 = new File("C:\Users\Ajay\*.mp3");
FileInputStream fis = new FileInputStream(fileMp3);
response.setContentType("audio/mpeg");
response.setHeader("Content-Disposition", "filename=\"hoge.txt\"");
response.setContentLength((int) fileMp3.length());
OutputStream os = response.getOutputStream();
try {
int byteRead = 0;
while ((byteRead = fis.read()) != -1) {
os.write(buffer, 0, byteRead);
}
os.flush();
} catch (Exception excp) {
downloadComplete = "-1";
excp.printStackTrace();
} finally {
os.close();
fis.close();
}
